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aalyn [17]
3 years ago
14

Find the coordinates of the center and the measure of the radius for a circle whose equation is (x - 3)^2 + (y - 7)^2 = 2.

Mathematics
1 answer:
zloy xaker [14]3 years ago
3 0

Answer:

A

Step-by-step explanation:

Equation for a circle of radius r, centered at (h,k):

(x-h)² + (y-k)² = r²

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f(x) is a quadratic function with x-intercepts at (−1, 0) and (−3, 0). If the range of f(x) is [−4, [infinity]) and g(x) = 2x^2
iren2701 [21]

Answer with Step-by-step explanation:

We are given that function f(x) which is quadratic function.

x -intercept of function f(x) at (-1,0) and (-3,0)

x-Intercept of f means zeroes of f

x=-1 and x=-3

Range of f =[-4,\infty)

g(x)=2x^2+8x+6=2(x^2+4x+3)

g(x)=0

2(x^2+4x+3)=0

x^2+4x+3=0

x^2+3x+x+3=0

x(x+3)+1(x+3)=0

(x+1)(x+3)=0

x+1=0\implies x=-1

x+3=0\implies x=-3

Therefore, x-intercept of g(x) at (-1,0) and (-3,0).

Substitute x=-2

g(-2)=2(-2)^2+8(-2)+6=8-16+6=-2

g(x)=2(x^2+4x)+6

g(x)=2(x^2+2\times x\times 2+4-4)+6=2(x^2+2\times x\times 2+4)-8+6

g(x)=2(x+2)^2-2

By comparing with the equation of parabola

y=a(x-h)^2+k

Where vertex=(h,k)

We get vertex of g(x)=(-2,-2)

Range of g(x)=[-2,\infty)

Zeroes of f and g are same .

But range of f and g are different.

Range of f contains -3 and -4 but range of g does not contain -3 and -4.

f and g are both quadratic functions.

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3 years ago
Find the slope of the line
grandymaker [24]

Answer: -4/5 or -0.8

Step-by-step explanation:

m= change in y / change in x

-4/ 5

8 0
2 years ago
Evaluate (3.5×10^13)-(1.4×10^12)/3×10^9
maw [93]

Answer:

11,200

Step-by-step explanation:

At first we use "BODMAS" rule.

Given,

(3.5×10^13)-(1.4×10^12)/3×10^9

So, we will break the brackets at first. With the help of excel, we can get the desired result. The following images will show you the step-by-step result.

Use "Number" instead of "general" in the excel sheet. You can use calculator too.

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