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3 years ago

9

Graphing Absolute Value Equations

2 answers:

Snowcat [4.5K]3 years ago

8 0

-x + 4 and that is the correct answer

Dennis_Churaev [7]3 years ago

3 0

Just X+4 when you multiply a negative by a negative you get a positive

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Use a graphing calculator to solve the equation -2sin(theta)= 1.2 in the interval from 0 to 2pi.

elena-s [515]

Answer:

$\theta=\pi +arcsin(\frac{3}{5})\approx 3.785\\\\\theta=2\pi -arcsin(\frac{3}{5} ) \approx 5.64$

Step-by-step explanation:

As you can see from the graph I attached you, the possible solutions in the interval from 0 to 2π are approximately:

$\theta=3.7\\\\and\\\\\theta=5.7$

So, it's useful to solve the equation too, in order to verify the result:

$-2sin(\theta)=1.2\\\\sin(\theta)=-\frac{3}{5}$

Taking the inverse sine of both sides:

$\theta=\pi +arcsin(\frac{3}{5})\approx 3.785\\\\\theta=2\pi -arcsin(\frac{3}{5} ) \approx 5.64$

Using this result we can conclude the solutions in the interval from 0 to 2π are approximately:

$\theta\approx 3.785\\\\\theta \approx 5.64$

8 0

3 years ago

One hundred items are simultaneously put on a life test. Suppose the lifetimes

romanna [79]

Answer:

a) $\mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}$

b) $\mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}$

Step-by-step explanation:

Given:

The lifetimes of the individual items are independent exponential random variables.

Mean = 200 hours.

Assume, Ti be the time between ( $i-1$ )st and the $ith$ failures. Then, the $T_{i}$ are independent with $\mathrm{T}_{\mathrm{i}}$ being exponential with rate $\frac{(101-i)}{200} .$

Therefore,

a) $E[T]=\sum_{i=1}^{5} E\left[\tau_{i}\right]$

$=\sum_{i=1}^{5} \frac{200}{101-i}$

$\therefore \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}$

$b)$

The variance is given by, $\mathrm{Var}[\mathrm{T}]=\sum_{i=1}^{5} \mathrm{Var}[T]$

$\therefore \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}$

7 0

3 years ago

Martin has a business washing cars. Last year he washed 20 cars a week. This year, he wants to increase his business to 1,200 ca

IgorC [24]

Great Question!

The last year part is extra information. 1200÷12 (months in a year)= 100

He will have to wash 100 cars each month.

8 0

2 years ago

kati45 [8]

The answer will be 0;7 and 2;112.

5 0

3 years ago

7 miles into kilometres

lozanna [386]

It is 11.265 kilometers

7 0

2 years ago

Read 2 more answers