The straight line joining the points A(3,-5) and B(6,k) has a gradient of 4.
Gradient is the slope
So the slope of the line joining the points A(3,-5) and B(6,k) is 4
Slope of line joining two points = 
A(3,-5) and B(6,k) are (x1,y1) and (x2,y2)
slope = 
slope = 
We know slope =4

Cross multiply and solve for k
k + 5 = 12
k = 7
The value of k = 7
Answer:
107%
Step-by-step explanation:
because if we look at the x-axis, Discount (%)
and look at 35 which is between 30 and 40
and start going up we get near 100
so
107%
or?
we use the two points and with that we find the slope first

plug in (20,62) and (10,32)
equals

simplify to 3
then we use
y - y1 = m (x - x1)
y - 62 = 3 (x - 20)
y - 62 = 3x - 60
add 60 from both sides
y - 2 = 3x
add 2 to both sides
y=3x+2
then plug in 35
y= 3(35) + 2
which is
107
Answer:
a) d = 3.6t
b) 10.8 miles
c) 1.2 hours
Step-by-step explanation:
For part a:
Slope of a line: y = mx + b
In this case, the equation would be: d = mt,
where m represents the speed Caden is walking at.
Note: b = 0 in this case because when Caden starts walking on the treadmill, he hasn't really covered any distance yet.
Therefore, plugging in a speed of 3.6 miles per hour, the equation is:
d = 3.6t
For part b:
This is a simple instance of plugging in 3 hours for our t value.
Therefore, d = 3.6 (3)
d = 10.8 miles
For part c:
In this case, we are given that d = 4.32 miles.
Therefore, 4.32 = 3.6t
Dividing both sides by 3.6, we get
t = 1.2 hours
Answer:
3rd option
Step-by-step explanation:
Answer:
-3x^4 + 5x^3 - 33x^2 + 25x - 3
//Hope it helps and it's right.