Nice, already in vertex form
y=a(x-h)^2+k
(h,k) is vertex
therfor since (-3,6) is vertex
we are looking for something like
y=a(x-(-3))^2+6 simplified to
y=a(x+3)^2+6
A is ansre
Area of a triangle is 1/2 x base x height:
Area = 1/2 x 8 x 20.5 = 82 square cm.
It is hone-half the area of a rectangle with dimensions 20.5 by 8 cm.
Try this solution:
1. the standart form of the circle is: (x-x₀)²+(y-y₀)²=r², where point (x₀;y₀) - the cetre of the given circle, r - radius of the given circle.
2. Using r=7 and coordinates of the centre (0;0) it is possible to make up the required equation:
(x-0)²+(y-0)²=7²;
x²+y²=49.
