Answer:
the average of this new list of numbers is 94
Step-by-step explanation:
Hello!
To answer this question we will assign a letter to each number for the first list and the second list of numbers, remembering that the last number of the first list is 80 and the last number of the second list is 96
for the first list
for the new list
To solve this problem consider the following
1.X is the average value of the second list
2. We will assign a Y value to the sum of the numbers a, b, c.
a + b + c = Y to create two new equations
for the first list
solving for Y
Y=(90)(4)-80=280
Y=280=a+b+c
for the second list
the average of this new list of numbers is 94
Answer:
g(-4)=3
Step-by-step explanation:
g(x)=-x-1
g(-4)=-(-4)-1
g(-4)=4-1
g(-4)=3
All estimating problems make the assumption you are familar with your math facts, addition and multiplication. Since students normally memorize multiplication facts for single-digit numbers, any problem that can be simplified to single-digit numbers is easily worked.
2. You are asked to estimate 47.99 times 0.6. The problem statement suggests you do this by multiplying 50 times 0.6. That product is the same as 5 × 6, which is a math fact you have memorized. You know this because
.. 50 × 0.6 = (5 × 10) × (6 × 1/10)
.. = (5 × 6) × (10 ×1/10) . . . . . . . . . . . by the associative property of multiplication
.. = 30 × 1
.. = 30
3. You have not provided any clue as to the procedure reviewed in the lesson. Using a calculator,
.. 47.99 × 0.6 = 28.79 . . . . . . rounded to cents
4. You have to decide if knowing the price is near $30 is sufficient information, or whether you need to know it is precisely $28.79. In my opinion, knowing it is near $30 is good enough, unless I'm having to count pennies for any of several possible reasons.
Gosh, when I saw that my mind went blank
