Answer:
1194 students last year
Step-by-step explanation:
The problem statement tells us ...
98% × (students last year) = 1170
Dividing by 98%, we get ...
1170/0.98 = (students last year) = 1193.88 ≈ 1194
___
<em>Check</em>
1170/1194 = 0.979899... ≈ 0.98 = 98%
Sn = (a1) x (1 - r^n) / (1 - r)
Substituting the known values:
S5 = (6) x (1 - (1/3)^5) / (1 - 1/3) = 242/27 = 8 24/27 = 8 8/9
k = 13The smallest zero or root is x = -10
===============================
Steps:
note: you can write "x^2" to mean "x squared"
f(x) = x^2+3x-10
f(x+5) = (x+5)^2+3(x+5)-10 ... replace every x with x+5
f(x+5) = (x^2+10x+25)+3(x+5)-10
f(x+5) = x^2+10x+25+3x+15-10
f(x+5) = x^2+13x+30
Compare this with x^2+kx+30 and we see that k = 13
Factor and solve the equation below
x^2+13x+30 = 0
(x+10)(x+3) = 0
x+1 = 0 or x+3 = 0
x = -10 or x = -3
The smallest zero is x = -10 as its the left-most value on a number line.
Please mark brainliest
<em><u>Hope this helps.</u></em>
Answer:
y = 1/2 (2)x
Step-by-step explanation:
Using the equation y = abx , substitute both of your given points into that equation.
2 = ab2 and 4 = ab3 Solve each equation for a.
2⁄b2 and 4⁄b3 = a Therefore, 2⁄b2 = 4⁄b3
Cross multiply: 2b3 = 4b2 Divide both sides by b2
2b = 4 a = 2/4 = 1/2
b = 2
