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3 years ago

Can u help me in this plz plz

Mathematics

1 answer:

e-lub [12.9K]3 years ago

7 0

3. A square is a rhombus in which all the angles equal (to 90°).

4. 20 : 24 ratio that the ball picked wont be green

5. false

11. 15

12. half a chance (1/2)

13. 51

16. 9.79 × 10^-5

17. 4y = 29

18. b) 6.1

19. 80

20. x = -8/7

30. Area ≈ 7982.79

34. check the picture i attached for the histogram

THIS TOOK SO LONG

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What is the value of this expression? 2.4 27.316

Rom4ik [11]

Answer:

If it is 2.4 times 27.316, it is 65.5584

Step-by-step explanation:

7 0

2 years ago

g 78% of all Millennials drink Starbucks coffee at least once a week. Suppose a random sample of 50 Millennials will be selected

Tatiana [17]

Answer:

We know that n = 50 and p =0.78.

We need to check the conditions in order to use the normal approximation.

$np=50*0.78=39 \geq 10$

$n(1-p)=50*(1-0.78)=11 \geq 10$

Since both conditions are satisfied we can use the normal approximation and the distribution for the proportion is given by:

$p \sim N (p, \sqrt{\frac{p(1-p)}{n}})$

With the following parameters:

$\mu_ p = 0.78$

$\sigma_p = \sqrt{\frac{0.78*(1-0.78)}{50}}= 0.0586$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

We know that n = 50 and p =0.78.

We need to check the conditions in order to use the normal approximation.

$np=50*0.78=39 \geq 10$

$n(1-p)=50*(1-0.78)=11 \geq 10$

Since both conditions are satisfied we can use the normal approximation and the distribution for the proportion is given by:

$p \sim N (p, \sqrt{\frac{p(1-p)}{n}})$

With the following parameters:

$\mu_ p = 0.78$

$\sigma_p = \sqrt{\frac{0.78*(1-0.78)}{50}}= 0.0586$

6 0

3 years ago

Consider the volume of a rectangular pyramid, one whose base is not square. Does changing one of the three variables (length, wi

user100 [1]

Let

L------> the length of the base of the pyramid

W-----> the width of the base of the pyramid

H-----> the height of the pyramid

V------> Volume of a rectangular pyramid

we know that

V=(1/3)*[L*W]*H

the three variables are going to have the same influence on the volume

example

case a) let's change the variable L (we reduce the variable by half)

L=(1/2)*L

the new volume is equal to

V new=(1/3)*[(L/2)*W]*H-----> V new=(1/2)*V

the new volume is half the original volume

case b) let's change the variable W (we reduce the variable by half)

W=(1/2)*W

the new volume is equal to

V new=(1/3)*[(W/2)*L]*H-----> V new=(1/2)*V

the new volume is half the original volume

case c) let's change the variable H (we reduce the variable by half)

H=(1/2)*H

the new volume is equal to

V new=(1/3)*[L*W]*H/2-----> V new=(1/2)*V

the new volume is half the original volume

therefore

the answer is

the three variables have the same influence on the volume

4 0

3 years ago

Read 2 more answers

Solving systems of equations<br><br> X-2y=0<br> Y=2x-3

bearhunter [10]

$\left \{ {{x-2y=0} \atop {y=2x-3}} \right. \\\\Substitute\ second\ equation\ to\ first:\\\\x-2(2x-3)=0\\x-4x+6=0\\-3x=-6\ \ \ \ \ |:-3\\x=2\\\\y=2\cdot2-3\\y=4-3=1\\\\ \left \{ {{y=1} \atop {x=2}} \right.$

5 0

3 years ago

Read 2 more answers

The answer is 5:6:20 but can someone explain how plz?

Leya [2.2K]

The ratio of red to green is 5:6 which means that for every 5 red cars, there are 6 green cars

The ratio of green to blue is 3:10 telling us that for every 3 green cars, there are 10 blue cars.

The ratio 3:10 is equivalent to 6:20 after we multiply both parts by 2. This now says that for every 6 green cars, there are 20 blue cars.

------------------------------

Let's say we had 5 red cars, 6 green cars and 20 blue cars
Based on that info, we know that the ratio of red to green is 5:6
And the ratio of green to blue is 6:20 which reduces to 3:10

We don't reduce 6:20 to 3:10 however, since that would change the green count from 6 to 3. We want to keep the green count at 6.

So because there are 5 red cars, 6 green cars, and 20 blue cars in this example, and this example points to the proper ratios mentioned earlier, this means that the final answer is 5:6:20. This ratio cannot be reduced or simplified as there are no common factors (other than 1) for 5, 6, and 20.

4 0

2 years ago