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3 years ago

Can u help me in this plz plz

Mathematics

1 answer:

e-lub [12.9K]3 years ago

7 0

3. A square is a rhombus in which all the angles equal (to 90°).

4. 20 : 24 ratio that the ball picked wont be green

5. false

11. 15

12. half a chance (1/2)

13. 51

16. 9.79 × 10^-5

17. 4y = 29

18. b) 6.1

19. 80

20. x = -8/7

30. Area ≈ 7982.79

34. check the picture i attached for the histogram

THIS TOOK SO LONG

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Which decimal is equivalent to 8.100

larisa86 [58]

Answer:

81/10

Step-by-step explanation:

i just figured it out i really don't have one but i hope it helps

7 0

2 years ago

A university found that 20% of its students withdraw without completing the introductory statistics course. Assume that 20 stude

EleoNora [17]

Answer:

a) $P(X \leq 2)= P(X=0)+P(X=1)+P(X=2)$

And we can use the probability mass function and we got:

$P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115$

$P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576$

$P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369$

And adding we got:

$P(X \leq 2)=0.0115+0.0576+0.1369 = 0.2061$

b) $P(X=4)=(20C4)(0.2)^4 (1-0.2)^{20-4}=0.2182$

c) $P(X>3) = 1-P(X \leq 3) = 1- [P(X=0)+P(X=1)+P(X=2)+P(X=3)]$

$P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115$

$P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576$

$P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369$

$P(X=3)=(20C3)(0.2)^3 (1-0.2)^{20-3}=0.2054$

And replacing we got:

$P(X>3) = 1-[0.0115+0.0576+0.1369+0.2054]= 1-0.4114= 0.5886$

d) $E(X) = 20*0.2= 4$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=20, p=0.2)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Part a

We want this probability:

$P(X \leq 2)= P(X=0)+P(X=1)+P(X=2)$

And we can use the probability mass function and we got:

$P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115$

$P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576$

$P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369$

And adding we got:

$P(X \leq 2)=0.0115+0.0576+0.1369 = 0.2061$

Part b

We want this probability:

$P(X=4)$

And using the probability mass function we got:

$P(X=4)=(20C4)(0.2)^4 (1-0.2)^{20-4}=0.2182$

Part c

We want this probability:

$P(X>3)$

We can use the complement rule and we got:

$P(X>3) = 1-P(X \leq 3) = 1- [P(X=0)+P(X=1)+P(X=2)+P(X=3)]$

$P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115$

$P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576$

$P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369$

$P(X=3)=(20C3)(0.2)^3 (1-0.2)^{20-3}=0.2054$

And replacing we got:

$P(X>3) = 1-[0.0115+0.0576+0.1369+0.2054]= 1-0.4114= 0.5886$

Part d

The expected value is given by:

$E(X) = np$

And replacing we got:

$E(X) = 20*0.2= 4$

3 0

3 years ago

Sebastian leaves £3000 in the bank for two years.

nevsk [136]

40000 is the answer man shdjdorjnekdbebrjf

6 0

3 years ago

I want to put $580 until I saving account for one year. The rate of interest On the account was 6 1/2%. How much was the interes

Vanyuwa [196]

Answer:

The amount of interest earned for the year is $37.7

Step-by-step explanation:

The formula for simple interest is expressed as

I = PRT/100

Where

P represents principal or amount invested.

T represents the time

R represents the interest rate

I represents the interest

From the information given,

You want to put $580 into a saving account for 1 year. This means that

P = $580 and

T = 1 year

R = 6 1/2 = 6.5%

I = (580× 6.5×1)/100 = $37.7

5 0

3 years ago

A student translated the phrase below into an algebraic expression, and then evaluated it for g = one-fourth. Is the student's w

iragen [17]

Answer:

The correct evaluation is 1 1/3 (one and one-third) and not 16 and one-third

Step-by-step explanation:

The student was wrong in his evaluation because the correct result should be 1 1/3 (one and one-third) and not 16 and one-third

The expression '1/3 more than the product of four and a number' means

(4g + 1/3)

Evaluating the expression when g = 1/4

You will have

4×1/4 + 1/3

= 1/1 + 1/3

Find the LCM of 1 and 3 and add

= (3+1)/3

=4/3

= 1 1/3

The correct evaluation is 1 1/3 (one and one-third) and not 16 and one-third

6 0

3 years ago

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