Question

What are the endpoint coordinates for the midsegment of △BCD that is parallel to BC?

Answer 1

Answer:

The endpoint coordinates for the mid-segment are:  $(-2,-1)$ and $(1,0)$

Step-by-step explanation:

According to the given diagram, the coordinates of the vertices of $\triangle BCD$ are:   $B(-3,1), C(3,3)$ and $D(-1,-3)$

Now, the endpoints of the mid-segment of $\triangle BCD$ which is parallel to $BC$ will be the mid-points of sides $BD$ and $CD$.

Formula for the coordinate of mid-point :   $(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2})$, where $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ are two endpoints.

So, the mid-point of $BD$ will be:  $(\frac{-3-1}{2},\frac{1-3}{2})=(\frac{-4}{2},\frac{-2}{2})=(-2,-1)$

and the mid-point of $CD$ will be:  $(\frac{3-1}{2},\frac{3-3}{2})=(\frac{2}{2},\frac{0}{2})=(1,0)$

Thus, the endpoint coordinates for the mid-segment of $\triangle BCD$ that is parallel to $BC$ are  $(-2,-1)$ and $(1,0)$

Answer 2

Answer:

(-2,-1) and (1,0)

Step-by-step explanation: