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anastassius [24]

3 years ago

13

A farm has 5 brown cows and 10 white cows. A fence is open and a cow escapes. What is the probability that it will be a brown co

w? A.50% B.1/2 C. 33% D.20%

2 answers:

Amanda [17]3 years ago

7 0

Answer:

C

Step-by-step explanation:

Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just don’t want to waste my time in case you don’t want me to :)

Alexxx [7]3 years ago

3 0

Answer:

C

Step-by-step explanation:

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Solve for n <br> 10n+0.3=0.1+0.3

galina1969 [7]

Answer:

0.01 is the awnser can you put me as the brainlest awnser

Step-by-step explanation:

4 0

3 years ago

Write two inequalities to compare -5and -3

AleksandrR [38]

-3 > -5
-5 < -3
hope it helps, sorry if I'm wrong

6 0

3 years ago

Find the mass of the lamina that occupies the region D = {(x, y) : 0 ≤ x ≤ 1, 0 ≤ y ≤ 1} with the density function ρ(x, y) = xye

Alona [7]

Answer:

The mass of the lamina is 1

Step-by-step explanation:

Let $\rho(x,y)$ be a continuous density function of a lamina in the plane region D,then the mass of the lamina is given by:

$m=\int\limits \int\limits_D \rho(x,y) \, dA$ .

From the question, the given density function is $\rho (x,y)=xye^{x+y}$ .

Again, the lamina occupies a rectangular region: D={(x, y) : 0 ≤ x ≤ 1, 0 ≤ y ≤ 1}.

The mass of the lamina can be found by evaluating the double integral:

$I=\int\limits^1_0\int\limits^1_0xye^{x+y}dydx$ .

Since D is a rectangular region, we can apply Fubini's Theorem to get:

$I=\int\limits^1_0(\int\limits^1_0xye^{x+y}dy)dx$ .

Let the inner integral be: $I_0=\int\limits^1_0xye^{x+y}dy$ , then

$I=\int\limits^1_0(I_0)dx$ .

The inner integral is evaluated using integration by parts.

Let $u=xy$ , the partial derivative of u wrt y is

$\implies du=xdy$

and

$dv=\int\limits e^{x+y} dy$ , integrating wrt y, we obtain

$v=\int\limits e^{x+y}$

Recall the integration by parts formula: $\int\limits udv=uv- \int\limits vdu$

This implies that:

$\int\limits xye^{x+y}dy=xye^{x+y}-\int\limits e^{x+y}\cdot xdy$

$\int\limits xye^{x+y}dy=xye^{x+y}-xe^{x+y}$

$I_0=\int\limits^1_0 xye^{x+y}dy$

We substitute the limits of integration and evaluate to get:

$I_0=xe^x$

This implies that:

$I=\int\limits^1_0(xe^x)dx$ .

Or

$I=\int\limits^1_0xe^xdx$ .

We again apply integration by parts formula to get:

$\int\limits xe^xdx=e^x(x-1)$ .

$I=\int\limits^1_0xe^xdx=e^1(1-1)-e^0(0-1)$ .

$I=\int\limits^1_0xe^xdx=0-1(0-1)$ .

$I=\int\limits^1_0xe^xdx=0-1(-1)=1$ .

No unit is given, therefore the mass of the lamina is 1.

3 0

3 years ago

alicia cashed her paycheck and used half of her earnings to take three friends to dinner. She spent $42.15 on dinner and she bro

Svetllana [295]

X=42.15-20.00y
this is in x=y

3 0

3 years ago

Kathleen makes bracelets to sell in a booth at a local store. She spent $62.30 on supplies to make bracelets for the next month.

vodomira [7]

Answer:

$105.20

Step-by-step explanation:

Given that :

Cost of materials = $62.30

Cost of booth = $25 / month

Price per bracelet = $5.50

Profit of 35 bracelet is sold next month =?

Profit = Revenue - Expenses

Revenue = $5.50 * 35 = $192.50

Expenses = $25 + $62.30 = $87.30

Profit = $192.50 - $87.30

= $105.20

4 0

3 years ago