Jessica purchased items worth $41.23 at the local

An alcohol solution was made by mixing 6 fl. oz. of a 20% alcohol solution and 4 fl. oz. of a 5% alcohol solution. What is the c

Vsevolod [243]

The answer to your question is a

5 0

3 years ago

Which object will have more inertia? Object A that has a mass of 250 grams, Object B, that has a mass of 25,000 grams, or Object

anyanavicka [17]

Answer:

3. Object C.

Step-by-step explanation:

The inertia of an object is the measure of the force required to set it in motion. For two objects to have the same motion, the one with the greater mass will require a proportionately greater force to achieve the same motion.

Object C, with a mass of 1,250,000 grams (1,250 kg) will have the greatest inertia.

7 0

2 years ago

A new Youth Activity Center is being built in Hadleyville. The perimeter of the rectangular playing field is 442 yards. The leng

MissTica

Answer:

45 yards and 176 yards

Step-by-step explanation:

Perimeter of a rectangular playing field = 2(Length + width)

P = 2(L+W)..................... Equation 1

From the question,

Let the width of the rectangular playing field = x yards,

The the Length = 4x-4 yards.

Given: P = 442 yards.

Substitute these values into equation 1

442 = 2(4x-4+x)

442/2 = 5x-4

221 = 5x-4

5x = 221+4

5x = 225

x = 225/5

x = 45 yards.

Width = 45 yards.

Length = (45×4)-4 yards = 176 yards

Hence the dimensions of the playing field are, 45 yards and 176 yards

8 0

3 years ago

Landen spent LL hours at the beach last weekend. Matéo spent 15\%15% fewer hours at the beach than Landen did. Which of the foll

ivanzaharov [21]

Answer: 0.85 L or $\frac{85L}{100}$ or $\frac{17L}{20}$

Step-by-step explanation:

Since, According to the question,

Landen spent time at the beach last weekend = L hours

And, Matéo spent 15% fewer hours at the beach than Landen did.

Therefore, Number of hours spent by Matéo = (Time spent by Landen last week - 15 % of the Time spent by Landen last week ) hours

= 85% of the Time spent by Landen last week

= $\frac{85\times L}{100}$

= $\frac{85L}{100}$ Hours

= $\frac{17L}{20}$ Hours

= 0.85 L Hours

8 0

4 years ago

Read 2 more answers

For a test of population proportion H0: p = 0.50, the z test statistic equals 1.05. Use 3 decimal places. (a) What is the p-valu

sergiy2304 [10]

Answer:

(a) The p-value of the test statistic is 0.147.

(b) The p-value of the test statistic is 0.294.

(c) The p-value of the test statistic is 0.8531.

(d) None of the p-values give strong evidence against the null hypothesis.

Step-by-step explanation:

The p-value is well defined as the probability,[under the null hypothesis (H₀)], of attaining a result equivalent to or greater than what was the truly observed value of the test statistic.

We reject a hypothesis if the p-value of a statistic is lower than the level of significance α.

The null hypothesis for the test of population proportion is defined as:

H₀: p = 0.50

The value of z-test statistic is,

z = 1.05

(a)

The alternate hypothesis is defined as:

Hₐ: p > 0.50

Compute the p-value of the test statistic as follows:

$p-value=P(Z>1.05)\\=1-P(Z$

*Use a z-table for the probability value.

Thus, the p-value of the test statistic is 0.147.

(b)

The alternate hypothesis is defined as:

Hₐ: p ≠ 0.50

Compute the p-value of the test statistic as follows:

$p-value=2\times P(Z>1.05)\\=2\times 0.1469\\=0.2938\\\approx 0.294$

*Use a z-table for the probability value.

Thus, the p-value of the test statistic is 0.294.

(c)

The alternate hypothesis is defined as:

Hₐ: p < 0.50

Compute the p-value of the test statistic as follows:

$p-value= P(Z1.05)=1- 0.1469\\=0.8531$

*Use a z-table for the probability value.

Thus, the p-value of the test statistic is 0.8531.

(d)

The decision rule of the test is:

If the p-value of the test is less than the significance level α, then the null hypothesis is rejected at α% level of significance.

And if the p-value of the test is more than the significance level α, then the null hypothesis is failed to be rejected.

The most commonly used level of significance are:

α = 0.01, 0.05 and 0.10

The p-value for all the three alternate hypothesis are:

p-values = 0.147, 0.294 and 0.8531.

All the p-values are quite large compared to the α values.

Thus, none of the p-values give strong evidence against the null hypothesis.

The null hypothesis was failed to be rejected.

5 0

3 years ago