Please help!

1 answer:

6 0

Because
$\frac{f(x)}{x-3} = 2x^{2} + 10x - 1$
therefore
f(x) = (x-3)(2x² + 10x - 1) + k, where k = constant.

Because f(3) = 4, therefore k =4.
The polynomial is
f(x) = 2x³ + 10x² - x - 6x² - 30x + 3 + 4
= 2x³ + 4x² - 31x + 7

Answer: f(x) = 2x³ + 4x² - 31x + 7

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