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fgiga [73]
3 years ago
11

Name the property the equation illustrates 7+(4+4)=(7+4)+4

Mathematics
1 answer:
attashe74 [19]3 years ago
6 0

the associative property of addition. Try and memorize the different properties. youll need to know them later on. I hope this helped!

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Find the equation of the quadratic function f whose graph is shown below.<br> (-4,-1)<br> (-3,-3)
Cerrena [4.2K]

The equation of the quadratic function f whose graph is shown below is x² + 6.1x + 8.2

Find the diagram attached.

First, we need to get the zeros of the required function. The point where the curve cuts the x-axis is the zeros.

According to the graph, the curve cuts the x-axis at x = -2 and x = -4.1

The required factors will be (x+2) and (x+4.1)

Taking the product of the factors

f(x) = (x+2)(x+4.1)

f(x) = x²+4.1x+2x +8.2

f(x) = x² + 6.1x + 8.2

Hence the equation of the quadratic function f whose graph is shown below is x² + 6.1x + 8.2

Learn more here: brainly.com/question/11286627

4 0
3 years ago
Find the center, vertices, and foci of the ellipse with equation x squared divided by 400 plus y squared divided by 625 = 1
Inessa05 [86]

Answer:

x^2/400 + x^2/625

(x-0)^2/400) +(y-0^2/625)

x^2=400

X=sqrt. 400

x = 20

y^2=625

y = sqrt. 625

y= 25

a^2-c^2=b^2

sqrt 400-625 = c

20-25=c

The correct answer is c=-5

(-5,0)

(5,0)

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
I’m going to need a serious answer through this one or I’m screwed.
Elina [12.6K]

Answer:

A = 60 ft²

Step-by-step explanation:

the area (A) of the shaded sector is calculated as

A = area of circle × fraction of circle

   = 90 × \frac{240}{360}

   = 90 × \frac{2}{3}

    = 30 × 2

    = 60 ft²

5 0
2 years ago
Read 2 more answers
The lower supports are and the area of the two supports is square meters. The upper arch can be decomposed as one semicircle wit
Galina-37 [17]

Answer:

 The lower supports are <u>Congruent Rectangles</u> and the area of the two supports is<u> 24 square meters.</u>

The upper arch can be decomposed as one semicircle with radius<u> 6 </u>meters minus a semicircle with radius 3 meters.

The area of the archway is <u>(13.5 π</u> + 24) square meters.

Step-by-step explanation:

See attachment for the firgure,

In order to determine the area of archway = The area of upper support + area of lower support.

As given, the lower support are two congruent rectangles consists of dimension 3 m × 4 m

Therefore, the area of lower support can be written as,

The area of lower support = 3 × 4 + 3 × 4 = 12 + 12 = 24 square m.

Now, the upper support arch can be decomposed as the two concentric semi circles having radius 3 m and 6 m,

Hence, the area of the upper support = Area of semi circle having radius i.e 6 m - Area of semi circle having radius i.e 3 m

=> π6²/2 - π3²/2= 27π/2= 13.5π square m

Therefore, the area of the archway =  (13.5 π + 24) square meters

4 0
4 years ago
Help this is due tomorrow
nlexa [21]

Answer:

n = 1.40 (second option)

8 0
3 years ago
Read 2 more answers
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