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4 years ago

5

If cone b has a volume of 256 cubic centimeters and a height of 16 centimeters, determine the radius of the cone. 48 cm 4√3 cm c

m 16 cm

2 answers:

Aneli [31]4 years ago

7 0

By definition, the volume of a cone is given by:
v = (pi * r ^ 2 * h) / 3
Where,
r: radius
h: height
Clearing the radio we have:
r = root ((3 * v) / (pi * h))
Substituting values:
r = root ((3 * (256)) / (3.14 * (16)))
r = 3.91 cm
Answer:
The radius of the cone is:
r = 3.91 cm
Note: a response option is missing

AlekseyPX4 years ago

7 0

Answer:

I recently got done with a quiz, and this was the answer I got, 16/3 cm.

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yuradex [85]

Answer:

The weight of grapefruit is now 80 pound.

Step-by-step explanation:

Consider the provided information.

Let the x is the weight loss. The weight of grapefruit is 100 pounds and water is 92%. After evaporation water is 90%.

Thus the weight loss is:

$0.92\times100-0.90(100 - x) = x$

$92-90+0.90x=x$

$2=x-0.90x$

$2=0.1x$

$x=20$

Hence, the weight loss is 80 pounds.

Therefore, New weight is 100 - 20 = 80 pounds

The weight of grapefruit is now 80 pound.

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3 years ago

Am i right or wrong pls help

Leto [7]

Answer:

Your correct!

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3 years ago

Read 2 more answers

Andre45 [30]

Answer:

$a_n=-3(3)^{n-1}$ ; {-3,-9, -27,- 81, -243, ...}

$a_n=-3(-3)^{n-1}$ ; {-3, 9,-27, 81, -243, ...}

$a_n=3(\frac{1}{2})^{n-1}$ ; {3, 1.5, 0.75, 0.375, 0.1875, ...}

$a_n=243(\frac{1}{3})^{n-1}$ ; {243, 81, 27, 9, 3, ...}

Step-by-step explanation:

The first explicit equation is

$a_n=-3(3)^{n-1}$

At n=1,

$a_1=-3(3)^{1-1}=-3$

At n=2,

$a_2=-3(3)^{2-1}=-9$

At n=3,

$a_3=-3(3)^{3-1}=-27$

Therefore, the geometric sequence is {-3,-9, -27,- 81, -243, ...}.

The second explicit equation is

$a_n=-3(-3)^{n-1}$

At n=1,

$a_1=-3(-3)^{1-1}=-3$

At n=2,

$a_2=-3(-3)^{2-1}=9$

At n=3,

$a_3=-3(-3)^{3-1}=-27$

Therefore, the geometric sequence is {-3, 9,-27, 81, -243, ...}.

The third explicit equation is

$a_n=3(\frac{1}{2})^{n-1}$

At n=1,

$a_1=3(\frac{1}{2})^{1-1}=3$

At n=2,

$a_2=3(\frac{1}{2})^{2-1}=1.5$

At n=3,

$a_3=3(\frac{1}{2})^{3-1}=0.75$

Therefore, the geometric sequence is {3, 1.5, 0.75, 0.375, 0.1875, ...}.

The fourth explicit equation is

$a_n=243(\frac{1}{3})^{n-1}$

At n=1,

$a_1=243(\frac{1}{3})^{1-1}=243$

At n=2,

$a_2=243(\frac{1}{3})^{2-1}=81$

At n=3,

$a_3=243(\frac{1}{3})^{3-1}=27$

Therefore, the geometric sequence is {243, 81, 27, 9, 3, ...}.

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