Answer:
ahhhhh swear that's scary honestly
Answer:
1.53x−14.23
Step-by-step explanation:
<em>simplify: </em>
5.03x−8.03−(3.5x+6.2)
<em>Distribute the Negative Sign:</em>
=5.03x−8.03−1(3.5x+6.2)
=5.03x−8.03−1(3.5x)+(−1)(6.2)
=5.03x−8.03−3.5x−6.2
<em>Combine Like Terms:</em>
=5.03x−8.03+−3.5x−6.2
=(5.03x−3.5x)+(−8.03−6.2)
=1.53x−14.23
Answer:
The graph is down below and if that helps u out pls mark me as brainliest:)
Step-by-step explanation:
~Alex
Answer:
S(1,2)
Step-by-step explanation:
The value that is being altered is the y value if you go from Q to T and then T to S. The x value = 1 and remains the same for point S.
To go from Q to T, you go from 8 to 5 on the y value. Remember x remains the same. That's three units (8 - 5 = 3)
To go from T to S must be 3 units as well, since the small diagonal is bisected. 5 - 3 = 2 is the answer.
So point S is noted as S(1,2)
MrBillDoesMath!
Answer to #4: 81/256 * s^8 * t^ 12
Comments:
(7x^3) ^ (1/2) = 7 ^ (1/2) * x^(3/2) where ^(1/2) means the square root of a quantity. The answer written (7x^3) is NOT correct.
---------------------
(1) (27s^7t^11)^ (4/3)
= 27^(4/3) * (s^7)^(4/3) * (t^11)^ (4/3)
As 27 = 3^3, 27 ^(4/3) = 3^4 = 81
(2) (-64st^2)^ (4/3) = (-64)^(4/3) * (s^4/3) * t(^8/3)
As 64 = (-4)^3, (-64)^(4/3) = (-4)^4 = +256
So (1)/(2) =
81 * s^(28/3)* t^(44/3)
------------------------------- =
256 s^(4/3) * t^((8/3)
81/256 * s ^ (28/3 - 4/3) * t^(44/3 - 8/3) =
81/256 * s^(24/3) * t (36/3) =
81/256 * s^8 * t^ 12
MrB
