4 years ago

what are the roots of the polynomial equation x3-7x=6x-12? Use a graphing calculator and a system of equations.

Mathematics

2 answers:

kvasek [131]4 years ago

5 0

Answer:

Step-by-step explanation:

Masteriza [31]4 years ago

3 0

X3-7x=6x-12
x3-7x-6x+12=0
x3-13x+12=0
(x-1)(x2+x-12)=0
Calculate delta of the second bracket:
delta = 1+4*12=49
sqrt(delta)=sqrt(49)=7
x_1=(-1-7)/2=-4
x_2=(-1+7)/2=3

(x-1)(x+4)(x-3)=0

Answear:
Roots: x=1, x=-4, x=3.

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Read 2 more answers

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Answer:

See Explanation

Step-by-step explanation:

The question is incomplete, as there are no options to select from.

However, a general explanation is as follows.

Given

$2\ cups = 1\ pint$

Required

Is $c = 2p$ a correct expression?

Let

$c = cups$

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