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3 years ago

what are the roots of the polynomial equation x3-7x=6x-12? Use a graphing calculator and a system of equations.

Mathematics

2 answers:

kvasek [131]3 years ago

5 0

Answer:

Step-by-step explanation:

Masteriza [31]3 years ago

3 0

X3-7x=6x-12
x3-7x-6x+12=0
x3-13x+12=0
(x-1)(x2+x-12)=0
Calculate delta of the second bracket:
delta = 1+4*12=49
sqrt(delta)=sqrt(49)=7
x_1=(-1-7)/2=-4
x_2=(-1+7)/2=3

(x-1)(x+4)(x-3)=0

Answear:
Roots: x=1, x=-4, x=3.

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Digiron [165]

Answer:

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Step-by-step explanation:

Given : $\dfrac{\sqrt 3 -1}{\sqrt 3+1}+\dfrac{\sqrt 3+1}{\sqrt 3-1}=a+\sqrt 3 b$

To find, The value of a and b

Solution,

Solving LHS of the given equation,

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Since,

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Alex787 [66]

Answer:

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Step-by-step explanation:

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3 years ago

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Answer:

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Step-by-step explanation:

Let the numbers be x and y.

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Answer:

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Step-by-step explanation:

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