Answer:
C. Cl2 and SF6
Explanation:
- According to the Graham's law of diffusion the rate of effusion or diffusion of a fixed mass of a gas is inversely proportional to the square root of its density or mass.
- For two gases; R1/R2 = √mm2/√mm1 ; where R1 and R2 are the rates of diffusion of the two gases respectively, while mm1 and mm2 are the molecular masses respectively.
Therefore, in this case we need two gases that have a ratio of their rates of diffusion as 1.43.
Thus; For Cl2 and SF6
Molecular mass of Cl2 is 70.906 g/mol, while that of SF6 is 146.06 g/mol
Therefore, the ratio of their rates of diffusion will be;
√(MM of SF6)/√(MM of Cl2) = √ 146.06/√70.906
= 1.4352
= 1.43
Therefore; the two gases required are Cl2 and SF6
Answer:
Option D will be the answer.
Answer:
To separate an insoluble solid from a soluble solid: Mixing the mixture with water, filtering out the insoluble solid, and then evaporating the water to isolate the soluble solid.
Explanation:
Answer:
0.20moles
Explanation:
1 mole Na contains 23 g Na
23 g Na =1 mole of Na
1 g Na= 1/23 moles of Na
4.6 g Na= 1/23×4.6= 4.6/23=0.2 moles
Therefore 0.2 moles are present in 4.6 g of Na
Answer:
so i never did this befor so i am sorry hope you get the answer
Explanation: