Answer:
i'm sorry i forgot this answer i just had it
Explanation:
Answer:
804 J
Explanation:
Step 1: Given data
- Mass of silver (m): 1.50 kg
- Initial temperature: -7.8 °C
- Final temperature: 15.0 °C
- Specific heat capacity of silver (c): 0.0235J·g⁻¹K⁻¹
Step 2: Calculate the energy required (Q)
We will use the following expression.
Q = c × m × ΔT
Q = 0.0235J·g⁻¹K⁻¹ × (1.50 × 10³g) × [15.0°C-(-7.8°C)]
Q = 804 J
Water Is A Liquid And Gravity Pulls Objects Up
<h3>Mass of aluminium : 13323.47 g</h3><h3>Further explanation</h3>
Given
Lf=latent heat of fusion of Al = 95 cal/g
Q = 1,265,730 cal
Required
mass of Aluminium
Solution
The heat to change the phase can be formulated :
Q = m.Lf (melting/freezing)
Input the value
1,265,730 cal = m . 95 cal/g
m = 1,265,730 cal : 95 cal/g
m = 13323.47 g
