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kiruha [24]
3 years ago
14

PLEASE PLEASE PLEASE HELP ME HAS TO BE TURNED IN AT 9:00

Chemistry
1 answer:
Kay [80]3 years ago
8 0

Answer:

Option D will be the answer.

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The maximum number of electrons in a valence shell is: <br> a. 2 <br> b. 8 <br> c. 18 <br> d. 32
vodomira [7]
B. 8

Although it may seem that transition metals would have more than 8 valence electrons, they in fact do not.
5 0
3 years ago
Read 2 more answers
Look at the graph
Vlad [161]

Answer:

a item dropping

Explanation:

KE is movement and PE is height. As it's falling it gets KE and falls downward giving it more KE and less PE

7 0
3 years ago
A 57.07 g sample of a substance is initially at 24.3°C. After absorbing of 2911 J of heat, the temperature of the substance is 1
icang [17]

Answer:

Approximately 0.551\; \rm J\cdot kg^{-1} \cdot \left(^\circ\! C \right)^{-1}.

Explanation:

The specific heat of a material is the amount of energy required to increase unit mass (one gram) of this material by unit temperature (one degree Celsius.)

Calculate the increase in the temperature of this sample:

\Delta T = (116.9 - 24.3)\; \rm ^\circ\! C= 92.6\; \rm ^\circ\! C.

The energy that this sample absorbed should be proportional the increase in its temperature (assuming that no phase change is involved.)

It took 2911\; \rm J of energy to raise the temperature of this sample by \Delta T = 92.6\; \rm ^\circ\! C. Therefore, raising the temperature of this sample by 1\; \rm ^\circ\! C (unit temperature) would take only \displaystyle \frac{1}{92.6} as much energy. That corresponds to approximately 31.436\; \rm J of energy.

On the other hand, the energy required to raise the temperature of this material by 1\; \rm ^\circ\! C is proportional to the mass of the sample (also assuming no phase change.)

It took approximately 31.436\; \rm J of energy to raise the temperature of 57.07\; \rm g of this material by 1\; \rm ^\circ C. Therefore, it would take only \displaystyle \frac{1}{57.07} as much energy to raise the temperature of 1\; \rm g (unit mass) of this material by 1\; \rm ^\circ \! C\!. That corresponds to approximately 0.551\; \rm J of energy.

In other words, it takes approximately 0.551\; \rm J to raise 1\; \rm g (unit mass) of this material by 1\; \rm ^\circ \! C. Therefore, by definition, the specific heat of this material would be approximately 0.551\; \rm J\cdot kg^{-1} \cdot \left(^\circ\! C \right)^{-1}.

8 0
3 years ago
What is the molar concentration of a sucrose solution prepared by dissolving 350.25 g of sucrose is enough deionized water to yi
vovangra [49]

The  molar concentration of a sucrose solution prepared by dissolving 350.25 g of sucrose is enough deionized water to yield a final solution volume of 500.00 mL is 2.048 M.

We must first obtain the number of moles of sucrose in the solution as follows;

Number of moles = mass/ molar

Mass of sucrose = 350.25 g

Molar mass of sucrose = 342 g/mol

Number of moles of sucrose= 350.25 g / 342 g/mol

= 1.024 moles

Recall that;

Number of moles = concentration × volume

concentration = Number of moles/volume

volume of solution = 500.00 mL or 0.5 L

concentration = 1.024 moles/0.5 L

concentration = 2.048 M

Learn more: brainly.com/question/13385951

3 0
3 years ago
104. Fill in the blanks to complete the table.
iren2701 [21]

Explanation:

Just a few things to remember:

  • # of neutrons  = Mass number - # protons
  • Mass number = # protons + # neutrons
  • Atomic Number = # of protons
  • # of electrons = # of protons - charge on the atom
  • Symbol - use the atomic number to find the element in the periodic table

3 0
3 years ago
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