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Schach [20]
3 years ago
15

Which of these methods could are used to separate an insoluble solid and soluble solid

Chemistry
1 answer:
Brilliant_brown [7]3 years ago
4 0

Answer:

To separate an insoluble solid from a soluble solid:  Mixing the mixture with water, filtering out the insoluble solid, and then evaporating the water to isolate the soluble solid.

Explanation:

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ryzh [129]
2,3,7,10,13 i did this yesterday can u mark me brainliest

3 0
3 years ago
A body found with rigor throughout the body
-BARSIC- [3]

Answer:

Can you move a body in rigor mortis?

Rigor mortis -- the lay version of it is stiffening of the joints. It really had nothing to do with the joints. It's the lack of chemical in the body, ATP, which is Adenosine Triphosphate. It goes away and you can now move the extremities easily after rigor mortis is gone away.

Explanation:

7 0
3 years ago
An empty beaker weighs 25.91 g. When completely filled with water, the beaker and its contents have a total mass of 333.85 g. Wh
Finger [1]

Answer:

The beaker holds 307.94  mL

Explanation:

As we know that the volume that beaker hold is the volume of water that occupied by it.

For this first we have to find mass of the water in the beaker

This can be calculated by the subtraction of beaker's weight from the weight of beaker and water.

     weight of water (m) = total weight - weight of beaker

Empty weight of beaker = 25.91 g

Weight of beaker with water = 333.85 g

Weight of water = 333.85 - 25.91 = 307.94 g

Density of water = 1 g/mL

We have

      Mass = Volume x density

      307.94  = Volume x 1

      Volume = 307.94  mL

The beaker holds 307.94  mL

3 0
3 years ago
An iron bar at 200c is placed in thermal contact with an identical iron bar at 120c in an isolated system
Step2247 [10]

Conduction: In the conduction, the heat is transferred from the hotter body to the colder body until the temperature on both bodies are equal.

In thermal equilibrium, there is no heat transfer as the heat is transferred till the temperature on the bodies are not same.

In the given problem, an iron bar at 200°C is placed in thermal contact with an identical iron bar at 120°C in an isolated system. After 30 minutes, the thermal equilibrium is attained. Then, the temperature on both iron bars are equal.Both iron bars are at 160°C in an isolated system.

But in an open system, the temperatures of the iron bars after 30 minutes would be less than 160°C. There will be heat lost to the surrounding. The room temperature is 25°C. There will be exchange of the heat occur between the iron bars and the surrounding. But It would take more than 30 minutes for both iron bars to reach 160°C because heat would be transferred less efficiently.

7 0
3 years ago
Read 2 more answers
Please help me with these?
Julli [10]

Question 5 is the second one.


8 0
3 years ago
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