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SIZIF [17.4K]
3 years ago
9

SOMEBODY PLZ HELP NUMBER 2

Mathematics
1 answer:
Artyom0805 [142]3 years ago
3 0

1) using a graphic tool

see attached figure n1

 ph=0-----> for t=0.1

ph=1-------- > for t=0.01

 2) using a graphic tool

see attached figure n2

 for t=0.5------------------ > ph=-0.699

 p(t) = −log10t------------------ > y= −log10t

convert the logarithmic function into an exponential function 

we have   10^y = 10^(<span><span>-log(t))   ------------ ></span> 10</span>^(y)<span> = 1/t ---------- > t = 10</span>^(<span>-y)
</span>

t = 10^(-y) 

<span><span>3)                 </span>p(t) = −log10t </span>

 which transformation results in a y-intercept (t=0)

<span> case
</span> <span>a) p(t) + 1</span>
p(t) = −log10t +1

Still here you can not have a Y intercept (t can't =0) since you would still have log(0) which is forbidden

<span>b) p(t + 1)</span>
p(t) = −log10(t+1)
<span>Here of course t can be zero since that just gives you log(1). So you have a Y-intercept. </span>

using a graphic tool

see attached figure n3b

for t=0------------------------ph=-0.9

 c)  −1 • p(t)

p(t) = log10t 

 Still here you can not have a Y intercept (t can't =0) since you would still have log(0) which is forbidden

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