Question

PLS HELP graph y=−x+6 8x−4y=−16

Answer 1

Answer:

The graph is shown below.

Step-by-step explanation:

Given:

$y=-x+6\\8x-4y=-16$

In order to graph these two lines, we find their x and y intercepts.

The x intercept of $y=-x+6$ is at $y=0$. So,

$0=-x+6\\x=6$

Therefore, x intercept is at $(6,0)$

The y intercept of  $y=-x+6$ is at $x=0$. So,

$y=0+6\\y=6$

Therefore, y intercept is at $(0,6)$

Now, similarly, we find the x and y intercepts of the other line.

The x intercept of $8x-4y=-16$ is at $y=0$. So,

$8x-4(0)=-16\\8x=-16\\x=\frac{-16}{8}=x=-2$

Therefore, x intercept is at $(-2,0)$

The y intercept of  $8x-4y=-16$ is at $x=0$. So,

$8(0)-4y=-16\\-4y=-16\\y=frac{-16}{-4}=y=4$

Therefore, y intercept is at $(0,4)$

Now, we plot these pair of points on a graph and then join the pairs of lines.

The graph is shown below.