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3 years ago

Forty tickets are sold for a raffle with two prizes. You buy two tickets. What is the probability that you will win both prizes

1 answer:

5 0

When you first pick a ticket, there are 2 winning tickets and 40 total tickets. This means that there is a 2/40 chance of your ticket being a winning one. This fraction can be reduced to 1/20.

After this, there will be 1 winning ticket left and 39 total tickets. There is a 1/39 chance of the next ticket being a winning one. We multiply these two fractions together to get our answer. 1/20 * 1/39 = 1/780, so there is a 1/780 chance of having 2 winning tickets.

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Help me with these math questions....

Nady [450]

Answer: cotθ

Step-by-step explanation:

tanθ * cos²θ * csc²θ

= $\dfrac{sin\theta}{cos\theta} * \dfrac{cos\theta*cos\theta}{} *\dfrac{1}{sin\theta*sin\theta}$

= $\dfrac{cos\theta}{sin\theta}$

= cotθ

Answer: B

Step-by-step explanation:

The parent graph is y = x²

The new graph y = -x² + 3 should have the following:

reflection over the x-axis
vertical shift up 3 units

Answers:

a. Quadrant II
b. negative
c. $\dfrac{\pi}{6}$
d. C
e. $-\dfrac{\sqrt{3}}{3}$

Explanation:

$\dfrac{17\pi}{6} - \dfrac{12\pi}{6} = \dfrac{5\pi}{6}$

a) Quadrant 2 is: $\dfrac{\pi}{2} < \theta < \pi$

b) In Quadrant 2, cos is negative and sin is positive, so tan is negative

c) $\pi-\dfrac{5\pi}{6}$ = $\dfrac{\pi}{6}$

d) the reference line is above the x-axis so it is negative --> $-tan\dfrac{\pi}{6}$

e) $tan(\dfrac{5\pi}{6})=\dfrac{1}{-\sqrt{3}}=-\dfrac{\sqrt{3}}{3}$

4 0

3 years ago

If 8 cakes cost $62.40, how much would 3 cakes cost?

Ilya [14]

Answer:

Step-by-step explanation:

Given,

Cost price of 8 cakes = $62.40

So,

Cost price of 1 cake = $ $\frac{62.40}{8}$

Therefore,

Cost price of 3 cakes

= $( $\frac{62.40}{8}$ × 3)

[On dividing 62.40 by 8]

= $(7.80 × 3)

[On multiplying]

= $23.40

Hence,

The required cost of 3 cakes is $23.40 (Ans)

3 0

3 years ago

Read 2 more answers

Find the distance between the points (3, -5) and (-6, -5).

Sophie [7]

ANSWER

EXPLANATION

We want to find the distance between the points (3, -5) and (-6, -5).

The given points have the same y-coordinates .

This means it is a horizontal line.

We use the absolute value method to find the distance between the two points.

We find the absolute value of the distance between the x-values.

The distance between the two points is

|3--6|=|3+6|=|9|=9

8 0

3 years ago

1.Graph f(x) = -1.5x +6 2.Graph f(x) = -1/2x-5

nalin [4]

Ans(1):

Given equation is f(x)=-1.5x+6

we can plug any number like x=0 and x=2 to find the f(x) also called y-value

plug x=0

f(x)=-1.5x+6 =-1.5*0+6 =0+6 =6

Hence first point is (0,6)

plug x=2

f(x)=-1.5x+6 =-1.5*2+6 =-3+6 =3

Hence first point is (2,3)

now we can graph both points then join them to get final graph of f(x)=-1.5x+6

---------------------

Ans(2):

We can repeat exactly same process for f(x) = -1/2x-5.

So the final graph will look like attached picture:

5 0

3 years ago

2. You throw a softball straight up into the air at a velocity of 30 feet per second. You release the softball at a height of 5.

nadya68 [22]

Answer:

$-16t^2+30t+5.8$

Step-by-step explanation:

We are given that

Initial velocity=30 ft/s

Initial position= $s_0=5.8 ft$

We have to write a mathematical model for height of the softball by using the position equation

The position equation on Earth's surface is given by

$h(t)=-16t^2+v_0t+s_0$

Where $v_0=$ Initial velocity

$s_0$ =Initial position

Substitute the values in the equation then, we get

$h(t)=-16t^2+30t+5.8$

Hence, the mathematical model for height of the softball is given by

$-16t^2+30t+5.8$

5 0

4 years ago