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Blababa [14]
3 years ago
5

Consider a single spin of the spinner.

Mathematics
2 answers:
alex41 [277]3 years ago
6 0

Answer:

"landing on a shaded portion and landing on a 3"

"landing on an unshaded portion and landing on a number less than 2 "

Step-by-step explanation:

Mutually exclusive means the events will have no intersection.

Let's look at your first choice:

"landing on a shaded portion and landing on an even number"

Landing on a shaded portion would be 1 or 4.

Landing on an even number would be 2 or 4.

There is an intersection (they contain a common element), the 4.

These events are not mutually exclusive.

Let's look at your second choice:

"landing on a shaded portion and landing on a number greater than 3"

Landing on a shaded portion would be 1 or 4.

Landing on a number greater than 3 would be just 4.

There is an intersection; they both contain 4.

These events are not mutually exclusive.

Let's look at your third choice:

"landing on a shaded portion and landing on a 3"

Landing on a shaded portion would be 1 or 4.

Landing on 3 would just be 3.

There is no common elements in the lists listed.  These events have no intersection.

These events are mutually exclusive.

Let's look at your fourth choice:

"landing on an unshaded portion and landing on an odd number"

Landing on a unshaded portion would be 2 or 3.

Landing on an odd number would be 1 or 3.

There is an intersection; they both have 3 in common.

These events are not mutually exclusive.

Let's look at your fifth choice:

"landing on an unshaded portion and landing on a number less than 2 "

Landing on an unshaded portion would 2 or 3.

Landing on a number less than 2 would be 1.

There is no intersection.

These events are mutually exclusive.

Cloud [144]3 years ago
5 0

Answer:

2nd and 5th Option

2nd Option: Landing on a shaded portion and landing on a number greater than 3

5th Option: Landing on an unshaded portion and landing on a number less than 2

Step-by-step explanation:

edge 2020

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Hi :)<br> Can anyone help me out?
elena55 [62]

Answer:

number 5:

(0 minus 1) minus 3= negative 4

number 6:

(0-4)+3=-1

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3 years ago
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A flag pole casts a shadow that is 10 feet long. A nearby windmill casts a shadow that is 18 feet long. If the flag pole is 18 f
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Answer:

26

Step-by-step explanation:

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The graph of y=√x is shifted 3 units down and 2 units right. Which equation represents the new graph?
kolbaska11 [484]
The general form would be:  y = a \sqrt{x-b} + c  where 'a' is responsible for the magnitude of the function, 'b' is responsible for horizontal shift.and 'c' is responsible for vertical shift of the function.  

Your answer would be:  y =  \sqrt{x-2} -3

Looks like choice A
7 0
3 years ago
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HELP !!! | 20 Points.
RUDIKE [14]

Answer:

No. The ladder is too steep.

Step-by-step explanation:

Length of ladder = 17 feet.  This is the hypotenuse.

Side a of a right triangle = 16.6

To answer this, you need one of the trigonometric functions.  

Opposite = 16.5

hypotenuse = 17

The function you need is the sine function.

Sin(theta) = opposite / hypotenuse

sin(theta) = 16.5 / 17

Sin(theta) = 0.97059

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3 years ago
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Before a bag of flour can be sold, it must be 40 kilograms but can be within 0.5
Serjik [45]

Answer:

The minimum acceptable weight of the flour bag is 39.5 kg,

and its maximum acceptable weight is 40.5 kg

Step-by-step explanation:

Notice that the selling weight of the bag to be sold (x) needs to differ from 40 kg at most 0.5 kg. Therefore, we can write the following inequality:

|x-40|\leq 0.5

The inequality can be solve once we remove the absolute value symbol, and solve for the unknown "x". Recall that in order to solve it, we need to consider the two possible cases:

a) that the expression within the absolute value symbol is larger than or equal to zero, and b) that the expression is less than zero.

a) If x-40\geq 0 then its absolute value is equal to itself (x-40), and when we remove the absolute value symbols, we get:

x-40\leq 0.5\\x\leq 0.5+40\\x\leq 40.5\,\,kg

which means that the weigh "x" of the flour bag should be smaller or equal than 40.5  kg

b) If x-40, then the absolute value of this is its opposite : -x+40, and the inequality becomes:

-x+40\leq 0.5\\40\leq 0.5+x\\40-0.5\leq x\\39.5\leq x

which means that the weight of the flour bag must be larger than or equal to 39.5 kg

So, the minimum acceptable weight of the flour bag is 39.5 kg, and the maximum acceptable weight is 40.5 kg

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