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3 years ago

Consider a single spin of the spinner.

Mathematics

2 answers:

alex41 [277]3 years ago

6 0

Answer:

"landing on a shaded portion and landing on a 3"

"landing on an unshaded portion and landing on a number less than 2 "

Step-by-step explanation:

Mutually exclusive means the events will have no intersection.

Let's look at your first choice:

"landing on a shaded portion and landing on an even number"

Landing on a shaded portion would be 1 or 4.

Landing on an even number would be 2 or 4.

There is an intersection (they contain a common element), the 4.

These events are not mutually exclusive.

Let's look at your second choice:

"landing on a shaded portion and landing on a number greater than 3"

Landing on a shaded portion would be 1 or 4.

Landing on a number greater than 3 would be just 4.

There is an intersection; they both contain 4.

These events are not mutually exclusive.

Let's look at your third choice:

"landing on a shaded portion and landing on a 3"

Landing on a shaded portion would be 1 or 4.

Landing on 3 would just be 3.

There is no common elements in the lists listed. These events have no intersection.

These events are mutually exclusive.

Let's look at your fourth choice:

"landing on an unshaded portion and landing on an odd number"

Landing on a unshaded portion would be 2 or 3.

Landing on an odd number would be 1 or 3.

There is an intersection; they both have 3 in common.

These events are not mutually exclusive.

Let's look at your fifth choice:

"landing on an unshaded portion and landing on a number less than 2 "

Landing on an unshaded portion would 2 or 3.

Landing on a number less than 2 would be 1.

There is no intersection.

These events are mutually exclusive.

Cloud [144]3 years ago

5 0

Answer:

2nd and 5th Option

2nd Option: Landing on a shaded portion and landing on a number greater than 3

5th Option: Landing on an unshaded portion and landing on a number less than 2

Step-by-step explanation:

edge 2020

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2 years ago

Predict if the product will be greater than, less than or equal to the second factor 4/5 x 1 2/5 = y

Radda [10]

Answer:

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Step-by-step explanation:

Given the expression

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solving to determine the product value

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$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}$

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$=\frac{28}{5\times \:5}$

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$y=\frac{28}{25}=1.12$

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3 years ago

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