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3 years ago

Consider a single spin of the spinner.

Mathematics

2 answers:

alex41 [277]3 years ago

6 0

Answer:

"landing on a shaded portion and landing on a 3"

"landing on an unshaded portion and landing on a number less than 2 "

Step-by-step explanation:

Mutually exclusive means the events will have no intersection.

Let's look at your first choice:

"landing on a shaded portion and landing on an even number"

Landing on a shaded portion would be 1 or 4.

Landing on an even number would be 2 or 4.

There is an intersection (they contain a common element), the 4.

These events are not mutually exclusive.

Let's look at your second choice:

"landing on a shaded portion and landing on a number greater than 3"

Landing on a shaded portion would be 1 or 4.

Landing on a number greater than 3 would be just 4.

There is an intersection; they both contain 4.

These events are not mutually exclusive.

Let's look at your third choice:

"landing on a shaded portion and landing on a 3"

Landing on a shaded portion would be 1 or 4.

Landing on 3 would just be 3.

There is no common elements in the lists listed. These events have no intersection.

These events are mutually exclusive.

Let's look at your fourth choice:

"landing on an unshaded portion and landing on an odd number"

Landing on a unshaded portion would be 2 or 3.

Landing on an odd number would be 1 or 3.

There is an intersection; they both have 3 in common.

These events are not mutually exclusive.

Let's look at your fifth choice:

"landing on an unshaded portion and landing on a number less than 2 "

Landing on an unshaded portion would 2 or 3.

Landing on a number less than 2 would be 1.

There is no intersection.

These events are mutually exclusive.

Cloud [144]3 years ago

5 0

Answer:

2nd and 5th Option

2nd Option: Landing on a shaded portion and landing on a number greater than 3

5th Option: Landing on an unshaded portion and landing on a number less than 2

Step-by-step explanation:

edge 2020

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How many distinguishable 11 letter "words" can be formed using the letters in MISSISSIPPI?

SCORPION-xisa [38]

This is given by the multinomial coefficient:

$\dbinom{11}{1,4,4,2}=\dfrac{11!}{1!4!4!2!}=34650$

If you're not familiar with the multinomial coefficient, you may be able to see it more clearly if you count the number of possible combinations taking each distinct letter $n$ times, where $n$ is the number of times it shows up in the original word.

$\underbrace{\dbinom{11}1}_{\text{M}}\underbrace{\dbinom{10}4}_{\text{I}}\underbrace{\dbinom64}_{\text{S}}\underbrace{\dbinom22}_{\text{P}}=\dfrac{11!}{1!10!}\dfrac{10!}{4!6!}\dfrac{6!}{4!2!}\dfrac{2!}{2!0!}=\dfrac{11!}{1!4!4!2!}$

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3 years ago

Which is not equivalent to the rest 13/20 66% 195/300 0.6500

Ganezh [65]

Hey there! :)

Let's change all the fractions and percents to decimal.
_____________________________________________________________

When changing fractions to decimal, divide the numerator by the denominator
When changing percents to decimal, remove the % sign and move the decimal to places to the left.
_____________________________________________________________

13 ÷ 20 = 0.65
66% = 0.66
195 ÷ 300 = 0.65
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The answer is 66% because it is the only one that isn't equivalent to 0.65

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3 years ago

if the probability of picking a pink jelly bean out of a bag is 4/15, what is the probability of not picking a pink jelly bean

KiRa [710]

Answer:

The probability of not picking a pink jelly bean: 11/15

Step-by-step explanation:

As we know that the maximum value of the probability of an event would always be 1.

The reason is that '1' is certain that something would happen.

Given that the probability of picking a pink jelly bean out of a bag is 4/15.

Thus, the probability of not picking a pink jelly bean can be calculated by subtracting 4/15 from the maximum probability '1'.

i.e.

Probability of not picking a pink jelly bean = max probability - 4/15

= 1 - 4/15

= 11/15

Therefore, the probability of not picking a pink jelly bean: 11/15

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