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Natalka [10]
3 years ago
10

If r = 5 units and x = 11 units, then what is the total surface area of the cylinder shown above?

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
7 0

Answer: 502.65

Step-by-step explanation: A= 2πrh + 2πr^ this is the formula for solving the surface area so now you must substitute

2·π·5·11+2·π·5^

6.28 · 55 + 2 π · 25

add and you will get 502.65 hope this helps mark me brainliest if it did

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Find the value of x that would make line p parallel to line r
Snowcat [4.5K]
There is a theorem that says if parallel lines are cut by a transversal, then same-side interior angles are supplementary (add up to 180 degrees).

If lines p and r were parallel, then angles 28 and (3x + 2) would add up to 180 degrees.

(28) + (3x + 2) = 180
3x + 30 = 180
3x = 150
x = 50
4 0
3 years ago
Use the commutative and associative properties of multiplication to write an expression equivalent to (4⋅5)⋅3.
Darina [25.2K]
Commutaive property says
ab=ba or expanded to say
abc=cba

associative peropty =
a(bc)=(ab)c

so using that
first mix them up knowing that we can move the parenthaseese
all possible equivelnt ones are
4*(5*3)
(3*5)*4
3*(5*4)
(3*4)*5
3*(4*5)
 
4 0
3 years ago
Alana and Ramiro are writing an article for the school newspaper about whether their classmates prefer to buy their lunch or bri
MrRissso [65]

Answer:Ramiro’s method is

Step-by-step explanation:

Did the assignment

3 0
3 years ago
Read 2 more answers
In a population of 10,000, there are 5000 nonsmokers, 2500 smokers of one pack or less per day, and 2500 smokers of more than on
Kazeer [188]

Answer:

In one month, we will have 4,950 non-smokers, 2,650 smokers of one pack and 2,400 smokers of more than one pack.

In two months, we will have 4,912 non-smokers, 2,756 smokers of one pack and 2,332 smokers of more than one pack.

In a year, we will have 4,793 non-smokers, 3,005 smokers of one pack and 2,202 smokers of more than one pack.

Step-by-step explanation:

We have to write the transition matrix M for the population.

We have three states (nonsmokers, smokers of one pack and smokers of more than one pack), so we will have a 3x3 transition matrix.

We can write the transition matrix, in which the rows are the actual state and the columns are the future state.

- There is an 8% probability that a nonsmoker will begin smoking a pack or less per day, and a 2% probability that a nonsmoker will begin smoking more than a pack per day. <em>Then, the probability of staying in the same state is 90%.</em>

-  For smokers who smoke a pack or less per day, there is a 10% probability of quitting and a 10% probability of increasing to more than a pack per day. <em>Then, the probability of staying in the same state is 80%.</em>

- For smokers who smoke more than a pack per day, there is an 8% probability of quitting and a 10% probability of dropping to a pack or less per day. <em>Then, the probability of staying in the same state is 82%.</em>

<em />

The transition matrix becomes:

\begin{vmatrix} &NS&P1&PM\\NS&  0.90&0.08&0.02 \\  P1&0.10&0.80 &0.10 \\  PM& 0.08 &0.10&0.82 \end{vmatrix}

The actual state matrix is

\left[\begin{array}{ccc}5,000&2,500&2,500\end{array}\right]

We can calculate the next month state by multupling the actual state matrix and the transition matrix:

\left[\begin{array}{ccc}5000&2500&2500\end{array}\right] * \left[\begin{array}{ccc}0.90&0.08&0.02\\0.10&0.80 &0.10\\0.08 &0.10&0.82\end{array}\right] =\left[\begin{array}{ccc}4950&2650&2400\end{array}\right]

In one month, we will have 4,950 non-smokers, 2,650 smokers of one pack and 2,400 smokers of more than one pack.

To calculate the the state for the second month, we us the state of the first of the month and multiply it one time by the transition matrix:

\left[\begin{array}{ccc}4950&2650&2400\end{array}\right] * \left[\begin{array}{ccc}0.90&0.08&0.02\\0.10&0.80 &0.10\\0.08 &0.10&0.82\end{array}\right] =\left[\begin{array}{ccc}4912&2756&2332\end{array}\right]

In two months, we will have 4,912 non-smokers, 2,756 smokers of one pack and 2,332 smokers of more than one pack.

If we repeat this multiplication 12 times from the actual state (or 10 times from the two-months state), we will get the state a year from now:

\left( \left[\begin{array}{ccc}5000&2500&2500\end{array}\right] * \left[\begin{array}{ccc}0.90&0.08&0.02\\0.10&0.80 &0.10\\0.08 &0.10&0.82\end{array}\right] \right)^{12} =\left[\begin{array}{ccc}4792.63&3005.44&2201.93\end{array}\right]

In a year, we will have 4,793 non-smokers, 3,005 smokers of one pack and 2,202 smokers of more than one pack.

3 0
3 years ago
Which of the following correctly expresses the number 65.824?
JulijaS [17]

The expression of the decimal number 65.8246 in word form is; tens + 5 ones + 8 tenths + 2 hundredths + 4 thousandths​

<h3>How to express decimal numbers?</h3>

A decimal is a number that consists of a whole and a fractional part. Decimal numbers lie between integers and represent numerical value for quantities that are whole plus some part of a whole.

Now, we are given the decimal number 65.824 to write in words. This can be written as;

6 tens + 5 ones + 8 tenths + 2 hundredths + 4 thousandths​

The reason for the above is that we can rewrite the given decimal in fraction form as;

60 + 5 + 8/10 + 2/100 + 4/1000

Read more about decimal expressions at; brainly.com/question/20053870

#SPJ1

4 0
2 years ago
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