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raketka [301]
3 years ago
8

A factory robot recently examined some bulbs, of which 2 were flawed and 18 were not. If 30 more bulbs are examined, predict how

many will be flawed.
Mathematics
1 answer:
Oksanka [162]3 years ago
5 0

Answer:

3 bulbs should be flawed

Step-by-step explanation:

2+ 18 = 20

20 bulbs were examined

2/20  = 1/10 were flawed

looking at the next 30 bulbs

30 * 1/10 = 3

3 of the next 30 bulbs should be flawed


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Answer:

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3 years ago
suppose the depth of the tide in a certain harbor can be modeled by y = 20 + 5 cos (pi/6 t), where y is the water depth in feet
Rom4ik [11]

Answer:

- high tide occurs at 12 noon and 12 midnight

- Low tide occurs at 6 a.m and 6 p.m

- maximum depth value = 20 ft

- Minimum depth value = 15 ft

Step-by-step explanation:

The depth is modelled as;

y = 20 + 5 cos (πt/6)

We are told that t = 0 represents 12:00 midnight.

This is high tide because at t = 0, the cos function will be at it's maximum value of 1 since cos 0 = 1.

Max depth value is;

y = 20 + 5(0)

y = 20 ft

Minimum depth value will be the low tide and it will be when the cos function is equal to -1.

Thus;

y = 20 + 5(-1)

y = 15 ft

Since t represents number of hours and since at 12 midnight, t = 0, thus; high tide will occur again at;

12 noon

Also, let's check for low tide.

Let's try t = 6 which means 6 a.m

Thus;

y = 20 + 5 cos (π(6)/6)

y = 20 + 5 cos π

Cos π has a value of -1

Thus;

y = 20 + 5(-1)

y = 20 - 5

y = 15 ft

Thus;

Low tide occurs at 6 a.m and 6 p.m

5 0
3 years ago
What is 751+567+4637+3783+3748​
anastassius [24]

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Answer:

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Step-by-step explanation:

Volume of cube = a^3

a= 9m

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3 years ago
Write the solution of the inequality in set builder notation: 2(3p-11)&gt;=-16
Dima020 [189]
The answer would be 
p≥1

hope this helps :3
8 0
3 years ago
Read 2 more answers
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