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Helga [31]
3 years ago
14

What is the equation of this circle in standard form M(2,4) N(9,4) these are coordinates across the diameter of the circle?

Mathematics
1 answer:
igomit [66]3 years ago
3 0
The standard form is

(x-xo)² + (y-yo)² = r²

Where xo,yo is the center of the circumference
and r is the radius.

We find the distance between the points to determine the <span>diameter

d=sqrt ((9-2)</span>² + (4-4)²<span>) = sqrt (49) = 7

The radius of the circumference is d/2 = 7/2 = 3.5

And we can see that those points are at the same coordinate y = 4 

The center is given then by , x = (9+2)/2 = 5.5
                                              y = (4+4)/2 = 4

The equation results

(x-5.5)</span>² + (y-4)² = (3.5)²<span>

</span>
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Answer:

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Step-by-step explanation:

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What is the vertex of the quadratic function f(x)=x2+6x+16? Write your answer
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Answer:

The vertex of the quadratic function is:

(x_{v}, y_{v})=\left(-3,\:7\right)

Step-by-step explanation:

Given the function

f\left(x\right)=x^2+6x+16

As the vertex of the form y=ax^2+bx+c is defined as:

x_v=-\frac{b}{2a}

As the quadratic function of parabola params are

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so

x_v=-\frac{b}{2a}

x_v=-\frac{6}{2\cdot \:1}

x_v=-3

Putting x_v=-3 to determine y_v

y_v=\left(-3\right)^2+6\left(-3\right)+16

y_v=3^2-18+16

y_v=9-2

y_v=7

Therefore, the vertex of the quadratic function is:

(x_{v}, y_{v})=\left(-3,\:7\right)

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