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Helga [31]
3 years ago
14

What is the equation of this circle in standard form M(2,4) N(9,4) these are coordinates across the diameter of the circle?

Mathematics
1 answer:
igomit [66]3 years ago
3 0
The standard form is

(x-xo)² + (y-yo)² = r²

Where xo,yo is the center of the circumference
and r is the radius.

We find the distance between the points to determine the <span>diameter

d=sqrt ((9-2)</span>² + (4-4)²<span>) = sqrt (49) = 7

The radius of the circumference is d/2 = 7/2 = 3.5

And we can see that those points are at the same coordinate y = 4 

The center is given then by , x = (9+2)/2 = 5.5
                                              y = (4+4)/2 = 4

The equation results

(x-5.5)</span>² + (y-4)² = (3.5)²<span>

</span>
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Answer:

90π yd²

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the surface area of a cylinder is the sum of the lateral area and twice the aera of one end of the cylinder:  π·d·l, where l represents the length of the cylinder.  Here, the lateral surface area is π·6 yd·12 yd, or 72π yd².

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The pattern is that the numbers in the right-most and left-most squares of the diamond add to the bottom square and multiply to reach the number in the top square.


For example, in the first given example, we see that the numbers 5 and 2 add to the number 7 in the bottom square and multiply to the number 10 in the top square.


Another example is how the numbers 2 and 3 in the left-most and right-most squares add up to the number 5 in the bottom square and multiply to the number 6 in the top square.


Using this information, we can solve the five problems on the bottom of the paper.


a) We are given the numbers 3 and 4 in the left-most and right-most squares. We must figure out what they add to and what they multiply to:

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Using this, we can fill the top square in with the number 6 and the bottom square with the number -5.


c) This time, we are given the numbers which we typically find by adding and multiplying. We will have to use trial and error to find the numbers in the left-most and right-most squares.


We know that 12 has the positive factors of (1, 12), (2,6), and (3,4). Using trial and error we can figure out that 3 and 4 are the numbers that go in the left-most and right-most squares.


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Answer:

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