Answer:
AY = 16
IY = 9
FG = 30
PA = 24
Step-by-step explanation:
<em>The </em><em>centroid </em><em>of the triangle </em><em>divides each median</em><em> at the ratio </em><em>1: 2</em><em> from </em><em>the base</em>
Let us solve the problem
In Δ AFT
∵ Y is the centroid
∵ AP, TI, and FG are medians
→ By using the rule above
∴ Y divides AP at ratio 1: 2 from the base FT
∴ AY = 2 YP
∵ YP = 8
∴ AY = 2(8)
∴ AY = 16
∵ PA = AY + YP
∴ AP = 16 + 8
∴ AP = 24
∵ Y divides TI at ratio 1: 2 from the base FA
∴ TY = 2 IY
∵ TY = 18
∴ 18 = 2
→ Divide both sides by 2
∴ 9 = IY
∴ IY = 9
∵ Y divides FG at ratio 1:2 from the base AT
∴ FY = 2 YG
∵ FY = 20
∴ 20 = 2 YG
→ Divide both sides by 2
∴ 10 = YG
∴ YG = 10
∵ FG = YG + FY
∴ FG = 10 + 20
∴ FG = 30
The answers to the question are are the equations
y = 0.08x²-1.6x+13
y = 0.08(x-10)²+5
<h3>How to solve for the system of equations</h3>
David starts at (20, 13) and skates along a path that can be modeled by a quadratic function with a vertex at (10, 5).
Vertex form of quadratic function is
y =
13 = a(x-10)²+5
let x = 20
a(20-10)²+5
13 = 100a + 5
take like terms
13 - 5 = 100a
8 = 100a
divide through by 100
a = 0.08
hence the equation would be
y = 0.08(x-10)²+5
Read more on equations here:
brainly.com/question/9621134
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