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solmaris [256]
3 years ago
10

Keisha says that 36 is a factor of18. Robert says 36 is a multiple of18. Who is correct?​

Mathematics
2 answers:
forsale [732]3 years ago
8 0

Answer:

robert

Step-by-step explanation:

Stolb23 [73]3 years ago
8 0
Robert is correct because a multiple is a number that can go into a number multiple times
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The variable Z is directly proportional to X. When X is 6, Z has the value 72.
motikmotik
Z\alpha x
Z=kX
where k is a constant of proportionality;
When x=6, z=72
72=6k
k=12
Z=12X
When x=13
Z=12*13
Z=156
8 0
4 years ago
Simplify: 8i^7+6i^5-5i^3-3i^2-7i-9
Dmitry_Shevchenko [17]
<span>Consider the remainder of the division of the power exponent of i by 4.
For a remainder r equal to 0, 1, 2 or 3, we have a power equal to 1, i, -1 or -i respectively, therefore:

</span>8i^7+6i^5-5i^3-3i^2-7i-9 =
8*(-i) + 6*i - 5*(-i) - 3*(-1) - 7i - 9 =
- 8i + 6i + 5i + 3 - 7i - 9 =
3 - 9 - 8i + 6i + 5i- 7i =
=\boxed{- 6 - 4i}

Answer:
\boxed{- 6 - 4i}

<span>

</span>
5 0
3 years ago
A computer chess game and a human chess champion are evenly matched. They play ten games. Find probabilities for the following e
AleksAgata [21]

Answer:

(a) The probability that each of them win five games is 0.2461.

(b) The probability that the computer wins seven games is 0.1172.

(c) The probability that the human wins at least 7 games is 0.1711.

Step-by-step explanation:

Let the random variable <em>X</em> = the human wins a chess game.

The probability that the human wins a game is, P (X) = <em>p</em> = 0.50.

The number of games played by the computer and the human is, <em>n </em>= 10.

The random variable X\sim Bin(n = 10,p=0.50)

The probability distribution of the Binomial random variable <em>X</em> is:

P (X=x)={n\choose x}p^{x}(1-p)^{n-x}={10\choose x}(0.50)^{x}(1-0.50)^{10-x}

(a)

If both the computer and the human wins five games each then the probability of the human winning 5 games is:

P (X=5)={10\choose 5}(0.50)^{5}(1-0.50)^{10-5}\\=252\times 0.03125\times0.03125\\=0.246094\\\approx 0.2461

Thus, the probability that each of them win five games is 0.2461.

(b)

If the computer wins 7 games then the number of games won by the human is, 10 - 7 = 3.

P (Computer winning 7 games) = P (Human winning 3 games)

The probability that the human wins 3 games is:

P (X=3)={10\choose 3}(0.50)^{3}(1-0.50)^{10-3}\\=120\times 0.125\times0.0078125\\=0.1171875\\\approx 0.1172

Thus, the probability that the computer wins seven games is 0.1172.

(c)

Compute the probability that the human wins at least 7 games as follows:

P(X\geq 7)=P(X=7)+P(X=8)+P(X=9)+P(X=10)\\={10\choose 7}(0.50)^{7}(1-0.50)^{10-7}+{10\choose 8}(0.50)^{8}(1-0.50)^{10-8}\\+{10\choose 9}(0.50)^{9}(1-0.50)^{10-9}+{10\choose 10}(0.50)^{10}(1-0.50)^{10-10}\\=0.1172+0.044+0.009+0.0009\\=0.1711

Thus, the probability that the human wins at least 7 games is 0.1711.

5 0
3 years ago
Part 2: Use congruency theorems to prove congruency​
Evgesh-ka [11]

Answer:  see proof below

<u>Step-by-step explanation:</u>

  Statement                      Reason

1. YO = NZ                      1. Given

2. OZ = OZ                     2. Reflexive Property

3. YO + OZ = YZ             3. Segment Addition Property

   NZ + OZ = NO

4. YO + OZ = NZ + OZ    4. Addition Property

5.  YZ = NO                     5. Substitution

6. ∠M ≅ ∠X                      6. Given

7. ∠N ≅ ∠Y                       7. Given

8. ΔMNO ≅ ΔXYZ           8. AAS Congruency Theorem

8 0
4 years ago
Read 2 more answers
She says that the coffee cup fountain actually holds about 400 gallons of coffee.
solmaris [256]

https://www.perfection-events.com/content/back-basics-coffee-essentials

6 0
3 years ago
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