Question

Enter the number in standard notation.

Answer 1

The length in standard notation is 0.05 meter

Solution:

Given that,

Jeremy measured the length of an ant as $5 \times 10^{-2}\ meter$

We have to write the length in standard notation

From given,

$Length = 5 \times 10^{-2}\\\\Length = \frac{5}{10^{2}}\\\\Simplify\\\\Length = \frac{5}{100}\\\\Length = 0.05$

Thus the length in standard notation is 0.05 meter

Method 2:

$length = 5 \times 10^{-2}\ meter$

Use the exponent of 10 to determine how many places to move the decimal point

Since exponent is -2, is negative

Thus, we have to move the decimal point to right 2 places

$5 \times 10^{-2} = 0.05$

Thus the length in standard notation is 0.05 meter