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3 years ago

When 2 lines cross, 2 pairs of vertical angles are formed. What is the sum of all 4 angles?

1 answer:

4 0

If 2 Lines are crossing together to make 2 pairs of Vertical Angles, the sum of all 4 Angles will always be equal to 360°.

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A rectangle has a perimeter of 26 cm and one of its sides has a length of 5 cm sketch a rectangle and label all of its sides len

vovikov84 [41]

Im thinking both shorter sides are 5cm, and the 2 longer sides are 8cm each... add them all together and you get 26cm

5 0

3 years ago

Read 2 more answers

Which of the following slopes of a line pass through points (1, -3) and (0, 2)?

Aloiza [94]

The slope of the line that passes through (1, -3) and (0, 2) is: B. m = -5.

<h3>What is the Slope of a Line?</h3>

Slope (m) = rise / run = change in y / change in x.

Given the points, (1, -3) and (0, 2):

Slope (m) = (-3 - 2)/(1 - 0)

Slope (m) = -5/1

Slope (m) = -5

Therefore, the slope of the line is: B. m = -5.

Learn more about the slope of a line on:

brainly.com/question/3493733

#SPJ1

6 0

1 year ago

Ron is tiling a countertop he needs to place 54 square titles in each of 8 rows to cover the counter

DiKsa [7]

He would only be able to make 6 rows with 3/4 of another

8 0

2 years ago

Can 29 be broken down to an even number

Novay_Z [31]

29 can not be broken down to an even number

8 0

3 years ago

Given the set of vertices, determine whether parallelogram ABCD is a rhombus, rectangle or square. List all that apply. A(7,-4),

Sloan [31]

Given:

Vertices of a parallelogram ABCD are A(7,-4), B(-1,-4), C(-1,-12), D(7, -12).

To find:

Whether the parallelogram ABCD is a rhombus, rectangle or square.

Solution:

Distance formula:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using distance formula, we get

$AB=\sqrt{(-4-(-4))^2+(-1-7)^2}$

$AB=\sqrt{(-4+4)^2+(-8)^2}$

$AB=\sqrt{0+64}$

$AB=8$

Similarly,

$BC=\sqrt{(-1-(-1))^2+(12-(-4))^2}=8$

$CD=\sqrt{(7-(-1))^2+(-12-(-12))^2}=8$

$AD=\sqrt{(7-7)^2+(-12-(-4))^2}=8$

All sides of parallelogram are equal.

$AC=\sqrt{(-1-7)^2+(-12-(-4))^2}=8\sqrt{2}$

$BD=\sqrt{(7-(-1))^2+(-12-(-4))^2}=8\sqrt{2}$

Both diagonals are equal.

Since, all sides are equal and both diagonals are equal, therefore, the parallelogram ABCD is a square.

We know that, a square is special case of rectangles and rhombus.

So, parallelogram ABCD is a rhombus, rectangle or square. Therefore, the correct option is c.

7 0

2 years ago