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2 years ago

The graph is a transformation of one of the basic functions. Find the equation that defines the function.

Mathematics

2 answers:

nikdorinn [45]2 years ago

8 0

Answer:

$y = 5-\sqrt{x}$

Step-by-step explanation:

Note that the graph shown is a transformation of the parent function

$y = \sqrt{x}$

The main function cuts the x-axis at x = 0 and has no negative values of y. In addition, the main function is always growing.

Note that the function shown is decreasing and intercepts the y-axis at y = 5.

Therefore, the graph of the main function has been reflected on the x-axis and displaced 5 units upwards.

If we do y = f(x) then to reflect the main function on the x-axis and move it upwards 5 units we make the following transformation

$y = -f(x) + 5$ .

Then the graphed function is:

$y = 5-\sqrt{x}$

SCORPION-xisa [38]2 years ago

6 0

Answer:

f(x) = -logx + 4.

Step-by-step explanation:

y = -log x approaches the point (0, 1) but this approaches (0, 5)

Looks like the graph of - log x + 4.

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katovenus [111]

Answer:

x = $\frac{7+\sqrt{47}\times i }{4}$

Step-by-step explanation:

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x + 2y = 6 ---------------(1)

y - 5 = $(x-2)^{2}$ ---------------(2)

y = $(x-2)^{2}$ + 5 ---------------(3)

Substitute (3) in (1) ,

x + 2( $(x-2)^{2}$ + 5 ) = 6

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x + 2( $x^{2} - 4x + 4$ + 5 ) = 6

$2x^{2} - 7x + 12=0$ --------------(4)

The roots of the quadratic equation $ax^{2} +bx+c$ is

x = $\frac{(-b) + \sqrt{(-b)^{2}-4 \times ac } }{2 \times a}$ -----------(5)

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x = $\frac{7 + \sqrt{(-7)^{2}-4 \times 24 } }{2 \times 2}$

x = $\frac{7+\sqrt{49-96}}{4}$

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3 years ago

drag the fractions that is equivalent to each repeating decimal each fractions may be used only once

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Answer:

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Step-by-step explanation:

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2 years ago

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Polly's Polls asked 1850 second-year college students if they still had their original major. According to the colleges, 65% of

suter [353]

Answer:

The probability that Polly's Sample will give a result within 1% of the value 65% is 0.6424

Step-by-step explanation:

The variable that assigns the value 1 if a person had its original major and 0 otherwise is a Bernoulli variable with paramenter 0.65. Since she asked the question to 1850 people, then the number of students that will have their original major is a Binomial random variable with parameters n = 1850, p = 0.65.

Since the sample is large enough, we can use the Central Limit Theorem to approximate that random variable to a Normal random variable, which we will denote X.

The parameters of X are determined with the mean and standard deviation of the Binomal that we are approximating. The mean is np = 1850*0.65 = 1202.5, and the standard deviation is √np(1-p) = √(1202.5*0.35) = 20.5152.

We want to know the probability that X is between 0.64*1850 = 1184 and 0.66*1850 = 1221 (that is, the percentage is between 64 and 66). In order to calculate this, we standarize X so that we can work with a standard normal random variable W ≈ N(0,1). The standarization is obtained by substracting the mean from X and dividing the result by the standard deviation, in other words

$W = \frac{X-\lambda}{\sigma} = \frac{X-1202.5}{20.5152}$

The values of the cummulative function of the standard normal variable W, which we will denote $\phi$ are tabulated and they can be found in the attached file.

Now, we are ready to compute the probability that X is between 1184 and 1221. Remember that, since the standard random variable is symmetric through 0, then \phi(-z) = 1-\phi(z) for each positive value z.

$P(1184 < X < 1221) = P(\frac{1184-1202.5}{20.5152} < \frac{X-1202.5}{20.5152} < \frac{1221-1202.5}{20.5152})\\ = P(-0.9018 < W < 0.9018) = \phi(0.9018) - \phi(-0.9018) = \phi(0.9018)-(1-\phi(0.9018))\\ = 2\phi(0.9018)-1 = 2*0.8212-1 = 0.6424$

Therefore, the probability that Polly's Sample will give a result within 1% of the value 65% is 0.6424.

Download pdf

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