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3 years ago

How do I this question?

Mathematics

1 answer:

mixas84 [53]3 years ago

7 0

You just do what it tells you to do.... divide by -5x... you are left with 10

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13 cm<br> L<br> 5 cm<br> Calculate the perimeter

aksik [14]

Answer:

Step-by-step explanation:

permeter is solved by doing length+length+width+width so therefore you would do 13+13+5+5 which equals 36 as your answer

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3 years ago

Read 2 more answers

What is 4 and 2/3 written as a radical?

TEA [102]

Answer:

14/3

Step-by-step explanation:

4 and 2/3 = 4 2/3 = 4 + 2/3 = 4/1 + 2/3 = 12/3 + 2/3 = 14/3

7 0

3 years ago

Comment all that apply

max2010maxim [7]

MCEA=90
mBEF=135
CEF is straight
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4 0

3 years ago

PLEASE ANSWER THIS ASAP!!!!

Anit [1.1K]

Answer:

82 units

Step-by-step explanation:

7 x 3 = 21

21 x 2 = 42

7 x 2 = 14

14 x 2 = 28

2 x 3 = 6

6 x 2 = 12

42 + 28 + 12 = 82

7 0

3 years ago

An open box is to be constructed so that the length of the base is 3 times larger than the width of the base. If the cost to con

natta225 [31]

Answer:

Step-by-step explanation:

Let assume that the volume = 88 cubic feet

Then:

$L = 3w --- (1)volume = l \times w \times h \\ \\ 88 = (3w) \times w \times h \\ \\ 3w^2 h= 88 \\ \\ h = \dfrac{88}{3w^2}--- (2) \\ \\$

The construction cost now is:

$C = 4(l \times w) + 2 ( w \times h) + 2(l \times h) \\ \\ C = 4(3w^2) + 2(w \times \dfrac{88}{3w^2}) + 2(3w \times \dfrac{88}{3w^2}) \\\\ C = 12w^2 + \dfrac{176}{3w} + \dfrac{176}{w}$

Now, to determine the minimum cost:

$\dfrac{dC}{dw}= 0 \\ \\ \implies 24 w - \dfrac{176}{3w^2}- \dfrac{176}{w^2}=0 \\ \\ 24 w ^3 = \dfrac{176}{w^2}(\dfrac{1}{3}+1) \\ \\ 24 w ^3 = \dfrac{176(4)}{3} \\ \\ w^3 = \dfrac{88}{3(3)}$

$w = \dfrac{88}{3(3)}^{1/3} \ feet$

Now;

$length = 3 ( \dfrac{88}{3(3)})^{1/3} \ feet$

$height = ( 88})^{1/3} (3)^{1/3} \ feet$

6 0

3 years ago