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AURORKA [14]
3 years ago
7

You mix 2/5 cup of red paint for every 1/4 cup of blue paint to make 15 /8 gallons of purple paint. How much red paint and blue

paint do you use?
Mathematics
1 answer:
Dafna11 [192]3 years ago
5 0

a- 2/5 + 1/4=.65 mixture of red and blue paint
(2/5) / .65 X 1.625=1 gallon of red paint
(1/4) / .65 X 1.625=5/8 gallons of blue paint, because
1 + 5/8=1 5/8 gallons of purple paint.

b-1/10 + 2/5 + 1/4=.75 mixture of white, red and blue paint

***FINAL answer: 1 gallon red, 5/8 gallon blue.***
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Orange juice is a common breakfast drink that contains citric acid. If the hydronium ion concentration is 3.4 × 10-4 in orange j
Lelu [443]

Answer:

3.5

Step-by-step explanation:

Given : the hydronium ion concentration is 3.4*10^{-4} in orange juice

To Find: what is the pH?

Solution :

Definition of pH : pH is the negative log of the molar hydrogen ion concentration

Formula of pH : - log [H+]

Since we are given H+ =  3.4*10^{-4}

So, substituting this value in formula :

pH = - log [3.4*10^{-4}]

pH = - log [3.4*0.0001]

pH = - log [0.00034]

pH = 3.468

pH = 3.468≈3.5

Thus the pH is 3.5

8 0
3 years ago
30008876543*98765435678
Sladkaya [172]

I got math error ahhhaha

8 0
3 years ago
Read 2 more answers
Ft?
VARVARA [1.3K]

Answer:

15 5/8 ft^3

Step-by-step explanation:

Volume of a cube = l x b x h

Given the Length of sides is

2 1/2

Change 2 1/2 to an improper fraction.

It becomes 5/2

Volume = 5/2 x 5/2 x 5/2

Multiply through

= 125/8

= 15 5/8 ft^3

5 0
3 years ago
What is an itrational number between 5 and 7
wariber [46]
Answer is √35 (square root of 35)

Reason: square root of 35 (which is = 5.9160797831.....) which is a non-terminating decimal, which means it is irrational.

An irrational number is any real number that cannot be expressed as a simple fraction or terminating decimals. There are many answers to this question.
7 0
2 years ago
Read 2 more answers
Use the following image to assist in your answer.<br> a =<br> - 6<br> - 9<br> - 4
vfiekz [6]

Step-by-step explanation:

Pythagoras' theorem for the smallest one :

c^2 = 4^2 + 6^2

c^2 = 16 + 36

c^{2} = 52

Pythagoras' theorem for the middle one :

b^{2} = 6^{2} + a^{2}

Pythagoras' theorem for the biggest one :

(4+a)^2 = c^2 + b^2

16 + 8a + a^2 = 52 + b^2

Using the formula before (for b^2) it becomes :

16 + 8a + a^2 = 52 + (6^2 + a^2)

16 + 8a + a^2 = 52 + 6^2 + a^2

16 + 8a = 52 + 6^2

16 + 8a = 52 + 36

16+8a = 88

8a = 88-16

8a = 72

a = \frac{72}{8}

a = 9

Verifying :

b^2 = 6^2 + a^2

b^2 = 36 + 81

b^2 = 117

b^{2} = 117

The biggest one :

(4+a)^2 = c^2 + b^2

(4+9)^2 = 52 + 117

13^2 = 169

True

8 0
3 years ago
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