Plz help due tomorrow
1 answer:
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Answer:
- ength (l) : (10-2*5/3) = 20/3
- width(w): (10 - 2*5/3) = 20/3
- height(h): 5/3
Step-by-step explanation:
Let x is the side of identical squares
By cutting out identical squares from each corner and bending up the resulting flaps, the dimension are:
- length (l) : (10-2x)
- width(w): (10-2x)
- height(h): x
The volume will be:
V = (10-2x) (10-2x) x
<=> V = (10x-2) (10-2x)
<=> V = 100x -20 - 20
+ 4
<=> V = 4 - 40
+ 100x
To determine the dimensions of the largest box that can be made, we need to use the derivative and and set it to zero for the maximum volume
dV/dx = 12 -80x + 100
<=> 12 -80x + 100 =0
<=> x = 5 or x= 5/3
You know 'x' cannot be 5 , because if we cut 5 inch squares out of the original square, the length and the width will be 0. So we take x = 5/3
=>
- length (l) : (10-2*5/3) = 20/3
- width(w): (10 - 2*5/3) = 20/3
- height(h): 5/3