All categories

2 years ago

7. An angle is in quadrant III with a reference angle of 20°, find the positive measure of the angle.

Mathematics

1 answer:

Aleks04 [339]2 years ago

3 0

Step-by-step explanation:

let the angle in 3rd quadrant be X

x+2=180

You might be interested in

3. A bag contains 46 blue ballons, 30 red ballons, and 24 purple ballons.

zalisa [80]

A because all of the numbers add up to 100 and there is 30 red so that would make it 30/100 and simplified it would be 3/10

3 0

3 years ago

What is the value of x for which (8-x)^2=x^2

I am Lyosha [343]

Answer:

x = 4

Step-by-step explanation:

${x}^{2} = {(8 - x)}^{2}$

$= > {x}^{2} = {x}^{2} - 16x + 64$

$= > {x}^{2} - {x}^{2} + 16x = 64$

$= > 16x = 64$

$= > x = \frac{64}{16} = 4$

5 0

2 years ago

Read 2 more answers

Help pls, will mark brainliest

BaLLatris [955]

Here , we are provided with a table which shows 5 consecutive terms of an arithmetic sequence . But before solving further , let's recall that ;

The n'th term of a Arithmetic Sequence let's say it be ${\sf T_n}$ is given by ;

${\boxed{\bf T_{n}=T_{1}+(n-1)d}}$

Where , <u>d</u> is the common difference

Now , here we are given with ;

${\quad \qquad \sf \blacktriangleright \blacktriangleright \blacktriangleright T_{1}=8 \: and \: T_{5}=-4}$

We have to find the 2nd , 3rd and 4th term respectively ,

Now , by using the above formula , 5th term can be written as ;

${: \implies \quad \sf T_{1}+(5-1)d=T_{5}}$

Putting the values and transposing 1st term to RHS , we have ;

${: \implies \quad \sf 4d = -4-8}$

${: \implies \quad \sf d=-\dfrac{12}{4}}$

${: \implies \quad \sf d=-3}$

Now , as we got the common difference , so we can find out the missing terms now ;

${: \implies \quad \sf T_{2}= T_{1}+(2-1)d}$

${: \implies \quad \sf T_{2}= 8 +d}$

${: \implies \quad \sf T_{2}= 8-3}$

${: \implies \quad \bf \therefore \: T_{2}= 5}$

Now

${: \implies \quad \sf T_{3}= T_{1}+(3-1)d}$

${: \implies \quad \sf T_{3}= 8 +2d}$

${: \implies \quad \sf T_{3}= 8-6}$

${: \implies \quad \bf \therefore \: T_{3}= 2}$

Also ,

${: \implies \quad \sf T_{4}= T_{1}+(4-1)d}$

${: \implies \quad \sf T_{4}= 8 +3d}$

${: \implies \quad \sf T_{4}= 8-9}$

${: \implies \quad \bf \therefore \: T_{4}= -1}$

Now , The given table can be written as ;

${\begin{array}{|c|c|c|c|c|c|}\cline{1-6} \bf n & \sf 1 & 2 & 3 & 4 & 5 \\ \cline{1-6} \bf T_{n} & \sf 8 & 5 & 2 & -1 & -4 \end{array}}$

Note :- Kindly view the answer from web , if you're not able to see the full answer from here ;

brainly.com/question/26750175

8 0

3 years ago

The square below represents one whole. Express the shaded area as a fraction, a decimal, and a percent of the whole. Fraction: D

Igoryamba

Answer:

Fraction = $\frac{19}{50}$

Decimal = 0.38

Percent = 38%

Step-by-step explanation:

Number of shaded rectangles = 38

Total number of rectangles = 100

Fraction represented by the shaded area = $\frac{\text{Number of blocks shaded}}{\text{Total number of blocks}}$

= $\frac{38}{100}$

= $\frac{19\times 2}{50\times 2}$

= $\frac{19}{50}$

Decimal form of the shaded area = $\frac{38}{100}$ = 0.38

Percent of the shaded area = $\frac{38}{100}$ = 38%

7 0

3 years ago

Review the graph. On a coordinate plane, a function starts at (negative StartFraction pi Over 2 EndFraction, negative 1), has an

aivan3 [116]

Answer:

Step-by-step explanation:

4 0

2 years ago