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jekas [21]
3 years ago
15

Write an equation in Slope-intercept form for the line that is perpendicular to the line y = 2x - 5 that passes through the give

n point (4,-2).
Mathematics
1 answer:
Yanka [14]3 years ago
6 0

Answer:

for perpendicular lines product of slope is -1

slope of other line is -0.5

(y+2)/(x-4)=-0.5

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If f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g – f)(3)?
Kryger [21]

For this case we have the following functions:

f (x) = 4 - x ^ 2\\g (x) = 6x

The first thing we must do for this case is to subtract both functions.

We have then:

(g - f) (x) = g (x) - f (x)

Substituting we have:

(g - f) (x) = (6x) - (4 - x ^ 2)

Rewriting we have:

(g - f) (x) = x ^ 2 + 6x - 4

Evaluating the obtained function for x = 3 we have:

(g - f) (3) = (3) ^ 2 + 6 (3) - 4\\(g - f) (3) = 23

Answer:

The value of the function evaluated at x = 3 is:

(g - f) (3) = 23

7 0
3 years ago
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Apply the Distributive Property Of multiplication in making an equivalent expression.
spin [16.1K]
2 x 4 = 8
2 x X = 2x
so 8 + 2x
4 0
3 years ago
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rosijanka [135]
Point S reflected over the y axis would be (9,0)
4 0
3 years ago
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The ΔPQR is right-angled at P, and PN is an altitude. If QN = 12 in and NR = 6 in, find PN, PQ, PR.
Goshia [24]
In the right triangle PQR:
Hypotenuse: QR = QN + NR = 12 + 6 = 18 cm
PN² = QN · NR
PN² = 12 · 6 = 72
PN = √72 = √(36 · 2 ) = 6√2 cm
PQ² = (6√2)² + 12² = 72 + 144 = 216
PQ = √216 = √(36 · 6 ) = 6√6 cm
PR² = 18² - (6√6)² = 324 - 216 = 108
PR = √108 = √(36 · 3) = 6√3 cm
Answer:
PN = 6√2 cm,
PQ = 6√6 cm,
PR = 6√3 cm.
3 0
3 years ago
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Misha Larkins [42]

Answer:

x=17

Step-by-step explanation:

The total degree of a hexagon is 720 degrees.

720-110-116=494.

(8x-1)+(6x-2)+(7x+19)+(5x+36)=494

x=17.

7 0
3 years ago
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