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tangare [24]
3 years ago
6

What is the measure of angle DEF to the nearest degree?

Mathematics
1 answer:
saveliy_v [14]3 years ago
8 0
I would say the answer is 35.
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If you invest $250.00 in an account that pays a simple interest rate of 4%, how long will you need to leave the money in the acc
labwork [276]

Answer:

Step-by-step explanation:

1. A = P(1 + rt) is the formula for simple interest where A is the final amount, P is the principal amount, r is the interest rate (annual), and t is the number of time periods, or time in years (most often)

2. $25 of interest means your total amount will be $275, so A = $275. P = $250. r = .04. We are trying to find t.

3. $275 = $250(1+.04t)

4. (275/250)(1.04) = t t = 1.05

5. This means you will need to wait 2 years to earn $25 in interest  

8 0
3 years ago
A customer at Marty’s Fruit Stand picks a sample of 3 oranges at random from a crate containing 60 oranges, of which 4 are rotte
pychu [463]

Answer:

340 ways

Step-by-step explanation:

Given:

Total number of oranges = 60

Number of rotten oranges = 4

Number of oranges picked = 3

Now, number of good oranges = Total number - Rotten oranges

                                                    = 60 - 4 = 56

Now, we need to pick at least two rotten oranges.

So, the possible outcomes can be as follows:

  1. 2 rotten oranges + 1 good orange = 3 oranges
  2. 3 rotten oranges + 0 good orange = 3 oranges

Now, number of ways of picking 'r' distinct objects from a total of 'n' objects is given  as:

^nCr=\frac{n!}{r!(n-r)!}

Now, picking 2 rotten oranges from a total of 4 rotten oranges is:

^4C_2=\frac{4!}{2!2!}=\frac{4\times 3\times 2}{4}=6

Similarly, picking 3 rotten oranges from a total of 4 rotten oranges is:

^4C_3 =\frac{4!}{3!\times1!}=\frac{4\times 3!}{3!}=4

Now, picking 1 good orange from a total of 56 good oranges is:

^{56}C_1=56

Picking 0 good oranges means picking no good oranges.

Therefore, the total number of ways of picking at least 2 rotten oranges is the sum of the above two possibilities and is given as:

At least 2 rotten out of 3 picked = (2 rotten and 1 good) or 3 rotten

                                                       = 6 × 56 + 4

                                                       = 336 + 4 = 340 ways

Therefore, there are 340 ways of picking at least 2 rotten oranges when 3 oranges are picked from a total of 60 oranges.

8 0
4 years ago
Find the values of a, b, and c in the equation
MatroZZZ [7]
I believe you have to use power rules for these so for the numerator (x^5yz^4)^3 the power outside of the bracket will multiply with the powers inside the bracket in order to simplify this part so the numerator of the fraction would be x^15y^3z^12 (because 5x3=15, 1x3=3, 4x3=12)
Next simplify the fraction this is done by subtracting the powers so x^15y^3z^12/x^3yz =x^12y^2z^11 (because any singular letter term ie y can also be seen as y^1, using this 15-3=12, 3-1=2, 12-1=11) this is your final answer so a=12 b=2 and c=11
3 0
3 years ago
3(x – 2) = 18 help bro.
liubo4ka [24]

Answer:

x = 8

Step-by-step explanation:

3x-6=18

+6 to both sides

3x=24

÷3 on both sides

x = 8

6 0
3 years ago
Please show me the steps of to do this <br> DON"T GIVE ME THE ANSWER<br> ASAP
kherson [118]

Answer:

B

Step-by-step explanation:

The number a . 10^{-2} is 8 times greater than b . 10^{-3}

thus, a . 10^{-2}  = 8b. 10^{-3}

multiply both sides by 10^{2}

we get a = 8b. 10^{-1} \\a = 0.8 b

if we take a = 2.5 and b = 3.1 we get 2.5/3.1 = 0.8

then B is the answer

8 0
3 years ago
Read 2 more answers
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