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Pachacha [2.7K]
3 years ago
14

What is 0.334 in expanded form

Mathematics
1 answer:
melamori03 [73]3 years ago
4 0
Just expand each number after the decimal. 0.300+0.030+0.004
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In order to earn extra money during the summer , omar is babysitting . The amount of money depends on the number of hours he bab
luda_lava [24]
M is dependent and h is independent
m=money and h=hours, p =money per hour
m=ph
6 0
3 years ago
Determine whether the statements are True or False. Justify your answer with an explanation.
frez [133]

Problem 1

<h3>Answer: False</h3>

---------------------------------

Explanation:

The notation (f o g)(x) means f( g(x) ). Here g(x) is the inner function.

So,

f(x) = x+1

f( g(x) ) = g(x) + 1 .... replace every x with g(x)

f( g(x) ) = 6x+1 ... plug in g(x) = 6x

(f o g)(x) = 6x+1

Now let's flip things around

g(x) = 6x

g( f(x) ) = 6*( f(x) ) .... replace every x with f(x)

g( f(x) ) = 6(x+1) .... plug in f(x) = x+1

g( f(x) ) = 6x+6

(g o f)(x) = 6x+6

This shows that (f o g)(x) = (g o f)(x)  is a false equation for the given f(x) and g(x) functions.

===============================================

Problem 2

<h3>Answer: True</h3>

---------------------------------

Explanation:

Let's say that g(x) produced a number that wasn't in the domain of f(x). This would mean that f( g(x) ) would be undefined.

For example, let

f(x) = 1/(x+2)

g(x) = -2

The g(x) function will always produce the output -2 regardless of what the input x is. Feeding that -2 output into f(x) leads to 1/(x+2) = 1/(-2+2) = 1/0 which is undefined.

So it's important that the outputs of g(x) line up with the domain of f(x). Outputs of g(x) must be valid inputs of f(x).

7 0
3 years ago
Find the value of x.
Dafna11 [192]

Answer:

61.7

we have:

cos 56⁰.x = 30/tan 41⁰

=>

x = \frac{30}{ \tan(41 {}^{0} ) \cos(56 {}^{0} )  }  = 61.7

6 0
2 years ago
Gina can trade empty bottles for money at the grocery store. She returned a few bottles worth $0.10 each and 6 bottles worth $0.
Irina18 [472]

Answer:

5 bottles

Step-by-step explanation:

a total of $0.80 was paid

6 $0.05 bottles were returned= $0.05×6= $0.30

remainder= $0.80-$0.30= $0.50

amount of $0.10 bottles returned= $0.50÷$0.10= 5

3 0
2 years ago
A blue whale calf weighed 2725 kilograms at birth. A blue whale calf gains 90 kilograms of weight each day for the first 240 day
Ivanshal [37]

Answer:the weight after 225 days is

22885 kilograms

Step-by-step explanation:

The initial weight of the blue whale calf at birth is 2725 kilograms. blue whale calf gains 90 kilograms of weight each day for the first 240 days after its birth. The weight increases in arithmetic progression. This means that the first term of the sequence, a is 2725, the common difference, d is 90.

The formula for the nth term of an arithmetic sequence is expressed as

Tn = a + (n - 1)d

Where

n is the number of terms of the sequence.

a is the first term

d is the common difference

We want to determine its weight, T225 after 225 days after it’s birth. It means that n = 225

Therefore

T225 = 2725 + (225 - 1)90

T225 = 2725 + 224×90 = 2725 + 20160

T225 = 22885

8 0
3 years ago
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