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4 years ago

What is the symbol for molarity?

Chemistry

2 answers:

Lubov Fominskaja [6]4 years ago

4 0

"M" I believe is the symbol for molarity.

GREYUIT [131]4 years ago

3 0

The symbol for molarity is M, and you can also use the unit mol/L in calculations since molarity is a ratio that describes the moles of solute per liter in solution.

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If ba+2 will reacts with n-3, the formula of the compound formed is:

Ivanshal [37]

If $Ba^{+2}$ will reacts with $N^{-3}$ , the formula of the compound formed is $Ba_3N_2$ .

<h3>What is an ionic compound?</h3>

Ionic compounds are neutral compounds made up of positively charged ions called cations and negatively charged ions called anions.

Barium is a metal element and Nitrogen is a non-metal element, so they form an ionic compound. To make the formula of an ionic compound, first, we need to see the valence of the atoms, that is, how many electrons it can donate or it has to gain to have 8 electrons in the valence layer (octet rule).

Barium is in family 2, so it has two electrons in its valence layer, so it must donate these two electrons; Nitrogen is in family 15, so it has 5 electrons ins its valence layer and must gain 3 electrons.

Writing the ions they must form:

$Ba^{+2}N^{-3}$

First came the cation (positive charge), then the anion (negative charge), and the charges must change between them, without the signal, and will inform how many atoms are necessary for which element:

$Ba_3N_2$

Hence, If $Ba^{+2}$ will reacts with $N^{-3}$ , the formula of the compound formed is $Ba_3N_2$ .

Learn more about the ionic compound here:

brainly.com/question/9167977

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6 0

2 years ago

Writing net ionic equation:<br> of cu with nitric acid

Lesechka [4]

The net ionic equation is

Cu(s) + 4H⁺(aq) + 4NO₃⁻(aq) ⟶ Cu²⁺(aq) + 2NO₃⁻(aq) + 2NO₂(g) + 2H₂O(ℓ)

<em>Molecular equation :</em>

Cu(s) + 4HNO₃(aq) ⟶ Cu(NO₃)₂(aq) + 2NO₂(g) + 2H₂O(ℓ)

<em>Ionic equation: </em>

Cu(s) + 4H⁺(aq) + 4NO₃⁻(aq) ⟶ Cu²⁺(aq) + 2NO₃⁻(aq) + 2NO₂(g) + 2H₂O(ℓ)

<em>Net ionic equation </em>

Cu(s) + 4H⁺(aq) + 4NO₃⁻(aq) ⟶ Cu²⁺(aq) + 2NO₃⁻(aq) + 2NO₂(g) + 2H₂O(ℓ)

<em>Note</em>: The net ionic equation is <em>the same as </em>the ionic equation because there are <em>no common ions</em> to cancel on opposite sides of the arrow.

3 0

3 years ago

Element used in bright flashlights

Mazyrski [523]

The element would be Neon. They are found in signs

8 0

4 years ago

11. if the ph of a solution increases from 2.0 to 4.0, the h3o^ ion concentration o a decreases by a factor of 2. b. decreases b

Wittaler [7]

Option (B) is the right answer.

Hydronium ion ( $H_{3}O^{+}$ ) concentration decreases by the <u>factor of 100</u>, if the pH of a solution increases from 2.0 to 4.0.

The hydrogen ion concentration in water is expressed by pH. Specific to aqueous solutions, pH is the <u>negative logarithm</u> of the hydrogen ion (H+) concentration (mol/L) : $pH = -log_{10}[H_{3}O^{+} ]$

Acidic solutions are those with a pH under 7, and basic solutions are those with a pH over 7. At this temperature, solutions with a pH of 7 are neutral (e.g.<u> pure water</u>). The pH neutrality <u>relies on temperature, falling below 7 if the temperature rises above 25 °C</u>.

<h3>Given: </h3>

pH1( initial pH) = 2.0

pH2( initial pH) = 4.0

[H3O+] = initial hydronium concentration

[H3O+]* = final hydronium concentration

<h3>Formula used : </h3>

$pH = -log_{10}[H_{3}O^{+}]$

<h3>Solution: </h3>

$pH = - log_{10}[H_{3}O^{+}] \\\\= > 10^{-pH} = [H_{3}O^{+}] \\\\similarly, \\\\10^{-pH} = [H_{3}O^{+}]*\\\\ = > 10^{-4} = [H_{3}O^{+}]*\\\\Now, \frac{[H_{3}O^{+}]*}{[H_{3}O^{+}]} = 10^{-2}$