All categories

3 years ago

Complete the first row in the table by filling in the missing information about a system at equilibrium.

Chemistry

2 answers:

enot [183]3 years ago

3 0

Answer:

$Q= K_{eq}$

Explanation:

Equilibrium system: It is defined as that condition when the rate of forward reaction is equal to rate of backward reaction.

It is also defined as that condition concentration of reactantsx and concentrations of products are constant .

Suppose a reaction

$aA+bB\leftrightharpoons cC+dD$

Equilibrium constant, $K_c=\frac{concentartion\;of\;products}{concentration;of;reactants}$

Equilibrium constant, $K_c=\frac{C^c\cdot D^d}{A^a\cdot B^b}$

When the reaction is not in equilibrium then reaction constant

$Q_c=\frac{C^c\cdot D^d}{A^a\cdot B^b}$

When the reaction is in equilibrium then the equilibrium constant is equal to reaction constant

Hence, $Q = K_c$

When Q < K then the concentrations of reactants are greater than the concentrations of products.

When Q > K then the concentrations of products are greater than the concentration of reactants.

Answer : $Q= K_{eq}$

Xelga [282]3 years ago

3 0

Answer:

A. Q = Keq

B. Equilibrium quantities of reactants and products

C. Q > Keq

D. System will shift toward reactants

E. Overabundance of reactants

F. System will shift toward products

Here are all the answers :)

You might be interested in

Can anyone help with 5 through 8? Please :(

Aleksandr [31]

Answer:

The answer to your question is below

Explanation:

5) Fe₂O₃(s) + 3H₂O ⇒ 2Fe(OH)₃ (ac) Synthesis reaction

6) 2C₄H₁₀(g) + 13O₂(g) ⇒ 8CO₂ (g) + 10H₂O Combustion reaction

7) 2NO₂ (g) ⇒ 2O₂ (g) + N₂ (g) Decomposition reaction

8) H₃P (g) + 2O₂ (g) ⇒ PO (g) + 3H₂O Single replacement reaction

4 0

3 years ago

What is the basis for the classification of changes in matter into physical and chemical changes quizlet

laiz [17]

Explanation:

The basis for classifying changes in matter into physical and chemical change is to see if a material is altered after going through a process.

In a physical change only the state of matter is usually altered especially its form or shape.

Chemical change alters a substance by producing new kinds that are totally different from it.

In a chemical change, new kinds of matter are usually formed.
Such changes are usually irreversible.
Change of state is a reversible process.

learn more:

Chemical change brainly.com/question/9388643

#learnwithBrainly

6 0

3 years ago

Which type of electromagnetic radiation has the longest wavelength?

Montano1993 [528]

Answer:

B. Infrared.

Explanation:

Referring to the electromagnetic spectrum, ultraviolet rays can be measured with a frequency of 10‐⁸, infrared has a frequency of 10‐⁵, visible radiation has a frequency of 0.5 x 10‐⁶ meanwhile X-rays show a frequency of 10‐¹⁰.

Hence, the largest magnitude among the rest goes to infrared rays, which makes B the correct answer.

8 0

3 years ago

Perform the calculations and determine the absolute and percent relative uncertainty. Express each answer with the correct numbe

Lana71 [14]

Answer:

Explanation:

Given the equation:

$\implies \dfrac{[9.8(\pm0.3)-2.31(\pm 0.01)]}{8.5(\pm0.6)}$

The absolute uncertainty in a measurement is the term used to describe the degree of inaccuracy.

The first step is to determine the algebraic value on the numerator.

Algebraic value = 9.8 - 231

= 7.49

The absolute uncertainty = $\sqrt{(abs. uncertainty_{v_1})^2+(abs. uncertainty_{v_2})^2}$

absolute uncertainty = $\sqrt{(0.3)^3 + (0.01)^2}$

= $\sqrt{0.09 + 0.0001}$

= 0.300167

∴

[9.8(±0.3) - 2.31(±0.01)] = 7.49(±0.300167)

The division process now is:

$\implies \dfrac{[9.8(\pm0.3)-2.31(\pm 0.01)]}{8.5(\pm0.6)}= \dfrac{7.49 (\pm 0.300167)}{8.5 (\pm0.6)}$

Relative uncertainty = $\dfrac{(\pm 0.300167)}{7.49}\times 100 \ , \ \dfrac{(\pm 0.6) }{8.5} \times 100$

Relative uncertainty = ±4.007565% , ±7.058824%

$\text{Relative uncertainty} = \sqrt{(4.007565)^2+(7.058824)^2}$

$\text{Relative uncertainty} = \sqrt{16.06057723+49.82699626}$

$\text{Relative uncertainty} = \sqrt{65.88757349}$

$\text{Relative uncertainty} = 8.117116$

≅ 8%

The algebraic value = $\dfrac{7.49}{8.5}$

= 0.881176

≅ 0.88

The percentage of the relative uncertainty = $\dfrac{\text{Absolute uncertainty }}{\text{calculated value} }\times 100$

By cross multiplying:

$\text{Absolute uncertainty} (\%) = \dfrac{\text{relative uncertainty} \times \text{calculated value}}{100}$

$\text{Absolute uncertainty} (\%) = \dfrac{8.117116\times 0.881176}{100}$

$\text{Absolute uncertainty} (\%) = 0.0715260$

$\mathbf{\text{Absolute uncertainty} (\%) \simeq 0.07}$

Finally:

$\mathbf{\implies \dfrac{[9.8(\pm0.3)-2.31(\pm 0.01)]}{8.5(\pm0.6)}= 0.88 \pm (0.07) \pm 8\%}$

8 0

3 years ago

What is the number of moles of beryllium in 36 g of Be?

GarryVolchara [31]

4 moles i believe cos mole = mass/ molar mass
mole =36/9
=4

3 0

3 years ago

Read 2 more answers