Identify the polynomial written in ascending order. 8x3+ 2x2− 6x − 11 2x2− 11 + 8x3− 6x −6x + 8x3− 11 + 2x2 −11 − 6x + 2x2+ 8x3

Nick has fraction 1 over 2 cup of syrup. He uses fraction 1 over 6 cup of syrup to make a bowl of granola.

SCORPION-xisa [38]

Part A) How many bowls of granola can Nick make with fraction 1 over 2 cup of syrup?

So if we have 1/2 cup of syrup and 1/6 is needed we can divide 1/2 by 1/6 to find our answer for part a.

1/2 / 1/6

"keep change flip" -> 1/2 x 6

answer -> 3

He can make 3 bowls of granola

Part B) On your own paper, draw a fraction model that shows the total number of bowls of granola that Nick can make with fraction 1 over 2 cup of syrup. Make sure to label the model. Below, explain your model in detail to describe how this model visually shows the solution for Part A.

(visual attatched)

You could say "This model visually shows the solution for Part A because each bowl of granola has 1/6 cup of syrup in it. The 1/2 cup is split into 3 different parts, as you can see"

(draw it neater though, it's hard on a computer with a mouse haha)

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

(second problem you commented)

Part A: How many 3 over 4 foot pieces can Clark cut from the 7 and 1 over 2 feet of wire? Show your work. (5 points)

First let us change 7 1/2 into an improper fractoin,

7 x 2 = 14 + 1 = 15/2

So then we can, as we did above, divide 15/2 by 3/4 which looks like:

15/2 / 3/4

keep, change, flip -> 15/2 x 4/3

60 / 6

answer -> 10

Clarck can cut 10 3/4 foot pieces.

Part B: Using the information in Part A, interpret the meaning of the quotient in terms of the two fractions given.

*I am honestly kind of confused by this question, so here is some words that are hopefully somewhat correct*

You could say here that "Calrck had 7 1/2 feet of wire. He needed 3/4 pieces, so when he cut it up he got 10 pieces. This is because 3/4 times 10 is 7 1/2 so this quotient makes sense with the two fractions given."

~~~~~~~~~~~~~`

Hopefully these are correct and help, have a nice day! :D

6 0

3 years ago

In Exercises 3–10, use the Chain Rule to calculate the partial derivatives. Express the answer in terms of the independent varia

sashaice [31]

I'll use subscript notation for brevity, i.e.

$\dfrac{\partial f}{\partial x}=f_x$

3.

$f(x,y,z)=xy+z^2\implies\begin{cases}f_x=y\\f_y=x\\f_z=2z\end{cases}$

$x(r,s)=s^2\implies\begin{cases}x_r=0\\x_s=2s\end{cases}$

$y(r,s)=2rs\implies\begin{cases}y_r=2s\\y_s=2r\end{cases}$

$z(r,s)=r^2\implies\begin{cases}z_r=2r\\z_s=0\end{cases}$

By the chain rule,

$f_r=f_xx_r+f_yy_r+f_zz_r=2xs+4zr=2s^3+4r^3$

$f_s=f_xx_s+f_yy_s+f_zz_s=2ys+2xr=6rs^2$

4.

$x(r,s,t)=r+s-2t\implies\begin{cases}x_r=1\\x_s=1\\x_t=-2\end{cases}$

$y(r,s,t)=3rt\implies\begin{cases}y_r=3t\\y_s=0\\y_t=3r\end{cases}$

$z(r,s,t)=s^2\implies\begin{cases}z_r=0\\z_s=2s\\z_t=0\end{cases}$

By the chain rule,

$f_r=f_xx_r+f_yy_r+f_zz_r=y+3xt=3rt+3r+3s-6t^2$

$f_s=f_xx_s+f_yy_s+f_zz_s=y+4zs=3rt+4s^3$

$f_t=f_xx_t+f_yy_t+f_zz_t=-2y+3xr=3r+3s-12rt$

8 0

3 years ago

81\3 using the distributive property

dalvyx [7]

The correct answer is 27

3 0

3 years ago

- Saint Pauls Mid

Goshia [24]

It should be noted that the median is the middle number in a sorted form whether ascending or descending while the interquartile range tells one the spread of the middle half of the distribution.

<h3>Solving median and interquartile range.</h3>

Your information is incomplete. Therefore, an overview will be given. To find the median, arrange the numbers given in an ascending or descending order and the middle number is the median.

Also, you can count how many numbers you've. If you have an odd number, divide the numbers by 2 and then round up in order to get the position of the median. In a case where it's an even number, divide it by 2 and go the number in the position and average it with the number that's in the next higher position in order to get the median.

In order to find the interquartile range, let's assume that the given numbers are 48, 52, 57, 64, 72, 76, 77, 81, 85, and 88. We've then numbers and this can be grouped into 5 each.

The first 5 will be 48, 52, 57, 64, and 72. In this case, the median in the first half which is Q1 is 57. The second 5 will be 76, 77, 81, 85, and 88. The median in the second half which is Q2 is 81. Therefore, the interquartile range will be:

= Q3 - Q1

= 81 - 57

= 24

Learn more about median and interquartile range on:

brainly.com/question/26151333

4 0

2 years ago

Class ends at 3:35 it’s 3:30 please answer! I’ll mark BRAINLIEST if right

Natalija [7]

The answer is 5 times deeper. Boat = 15
75/15 = 5

3 0

3 years ago