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liraira [26]
3 years ago
13

Otis paints the interior of a home for $45 per hour plus $75 for supplies. Shireen paints the interior of a home for $55 per hou

r plus $30 for supplies. The equations give the total cost for x hours of work for each painter. For how many hours of work are Otis's and Shireen's costs equal? What is the cost for this number of hours? Y= 45x + 75 - Otis Y= 55x + 30 - Shireen​
Mathematics
2 answers:
riadik2000 [5.3K]3 years ago
8 0

Step-by-step explanation:

you should only make one equation:

75 + 45x = 30 + 55x

subtract the 30 frim both sides, then subtract 45x from both sides. you are left with:

45 = 10x

Divide by 10 and get:

4.5 = x

After 4.5 hours, the cost is equal for either worker.

eimsori [14]3 years ago
4 0

Answer:

The cost will be equal at 4.5 hrs

Step-by-step explanation:

Otis paints the interior of a home for $45 per hour plus $ 75. Shireen paints the interior of a home for $ 55 per hour plus $30.

The total cost Y of Otis and Shireen's  for x hours are

Y= 45x + 75

Y= 55x + 30

For the cost to be equal

45x + 75  =  55x + 30

collect like terms

75 - 30 = 55x - 45x

45 = 10x

divide both sides by 10

x = 45/10

x = 4.5 hrs

The cost will be equal at 4.5 hrs

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Let F⃗ =2(x+y)i⃗ +8sin(y)j⃗ .
Alik [6]

Answer:

-42

Step-by-step explanation:

The objective is to find the line integral of F around the perimeter of the rectangle with corners (4,0), (4,3), (−3,3), (−3,0), traversed in that order.

We will use <em>the Green's Theorem </em>to evaluate this integral. The rectangle is presented below.

We have that

           F(x,y) = 2(x+y)i + 8j \sin y = \langle 2(x+y), 8\sin y \rangle

Therefore,

                  P(x,y) = 2(x+y) \quad \wedge \quad Q(x,y) = 8\sin y

Let's calculate the needed partial derivatives.

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Thus,

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Now, by the Green's theorem, we have

\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA = \int \limits_{-3}^{4} \int \limits_{0}^{3} (-2)\,dy\, dx \\ \\\phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-2y) \Big|_{0}^{3} \; dx\\ \phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-6)\; dx = -6x  \Big|_{-3}^{4} = -42

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Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

6 0
3 years ago
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Hope this helps!
7 0
3 years ago
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meriva

Answer:

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