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AURORKA [14]
3 years ago
14

FU

Mathematics
1 answer:
morpeh [17]3 years ago
4 0

Answer:

a^2 + b^2 = c^2

36^2 + 48^2 = 3600

Square root of 3600 = 60

So the diagonal measurement is 60"

Step-by-step explanation:

You might be interested in
What is the value of x? 12 inches 7 inches 49 inches 35 inches. ​
Papessa [141]

Answer:

98 inches or 8.16667 feet

Step-by-step explanation:

(12 + 7 + 45 + 35) = 98 divided by 12 = 8.16667

6 0
3 years ago
Help with a few questions pleaseeeeee
mel-nik [20]
29.99 * 3 =89.97 89.97 with 30% off = 62.98 and 5% of 62.98 =3.15 so 62.98 + 3.15 = 66.13$ 


180.00 + 14.95 + 8.95 = 203.09 - 15% = 173.44 + 4% = 180.38


5.65 + 5% of 5.65 = 5.93 

i think this is all right you might want to check my work!
3 0
4 years ago
In the figure shown, what is the measure of angle x?
mojhsa [17]
Angles in a triangle must add up to 180, so the missing angle inside the triangle is 180 - (70 + 40), which is 70.

Angles on a straight line (i.e. the line BD) must add up to 180, and because we know part of that angle is 70, x must be 180 - 70, which is 110.

Hence, x is 110 degrees.
5 0
3 years ago
Read 2 more answers
One-tenth of the cars in a car park are yellow. Another car arrives and now one-ninth of the cars are yellow. How many cars are
Triss [41]
There are 81 cars now in the car park! :D
4 0
3 years ago
Read 2 more answers
Two chess players, A and B, are going to play 7 games. Each game has three possibleoutcomes: a win for A (which is a loss for B)
Lina20 [59]

Answer:

A) the possible outcomes for individual game is 210 games.

B) The possible outcome for this is 357 games.

C) Then the Possible Games are 267 games.

Step-by-step explanation:

A) Total number of individual games are 7 in which A ends up with 3 wins which give 4 remaining games. then there are two draw games from them. and in the end the remaining games are losses so,we useformula for combination:

                       (7C3)*(4C2)=210 \ games

B) Now Player A has 4 point that gives us 5 possibilities until we reach 7 games. Similarly B have 3 points which is same as player A gives us 5 possibilities until we reach 7 games. thus those two cases for player A and Player B can be stated as:

           (7C3)+(7C3)*(4C2)+(7C1)*(6C6)+(7C2)*(5C4)=357\  games

C) Lets say that player A ahs 4 points and player B has 3 points and all seven games have been played so.

c1) If player A has 4 wins and 3 losses then last win have to be in 7th match thus:the answer is (6C3).

c2) If player A has 3 win, 2 draws and 3 losses thus it means that final match cannot be a loss thus the answer is (6C2)*(5C3).

c3) Now lastly if player A has 1 win and 5 draws we can arrange them arbitrarily thus the answer here is (7C1).

c4) now If player A has 2 wins, 4 draws and 2 losses thus answer is (6C1)*(6C2)

Sum of all the cases is

               (6C3)+(6C2)*(5C3)+(7C1)+(6C1)*(6C2)=267\ games

4 0
3 years ago
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