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just olya [345]
3 years ago
14

The equation to the problem

Mathematics
1 answer:
Margarita [4]3 years ago
8 0
3x+2y=30 okkkkkkkkkkkkkkkkkkkkkkkkk
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Help me plz this test is hard
kenny6666 [7]

Answer:

B I think

Step-by-step explanation:

7 0
2 years ago
Simplify. -10m+2m^4-13m-20m^4
Ulleksa [173]
First one:

you can add -10m and -13m but you can't add -10m and 2m^4 becuase the powers aren't the same so

when adding the like terms
look at the:
powers, (x^3 adds with x^3)
placehloder letter (x adds with x and y adds with y and so on)

-10m+2m^4-13m-20m^4
powers: m^1 and M^4
placeholders: all m


add
-10m-13m+2m^4-20m^4
-23m-18m^4




second one:
when multiplying exponents, you add with like
so if you multipliy
x^2yz^3 times x^4y^2z^2 thne you would get x^6y^3z^5
when multiply with coeficients
2x^2yz^3 times 4x^4y^2z^2=8x^6y^3z^5
so using associative property a(bc)=(ab)c
2/3 times p^4 times y^3 times y^4 times s^5 times 6 times p^2 times s^3
group like terms

(2/3 times 6) times (p^4 times p^2) times (y^3 times y^4) times (s^5 times s^3)
(4) times (p^6) times (y^7) times (s^8)
4p^6y^7s^8

8 0
3 years ago
The equation of a line given two points needs to be found. Samuel claims that slope-intercept form will generate the equation an
Zigmanuir [339]

The answer is:put the equation xa+yb=1 to the slope intercept form and find its slope and y-intercept.

3 0
3 years ago
a club is holding a raffle. Ten thousand tickets have been sold for $2 each. There will be a 1st prize of $3000, 3 second prizes
seropon [69]

Answer:

1000(1/20000) +

300(2/20000) +

10(20/20000) +

=

1800/20000 = .09

Step-by-step explanation:

Each ticket purchased is expected to win 9 cents

Each ticket purchased cost 75 cents

If you interpret expected winnings per ticket to include the cost then each ticket is expected to lose 66 cents.

4 0
3 years ago
A dog is leashed to the corner of a house. How much running area does the dog have? Round answer to the nearest square foot, if
sashaice [31]

Answer:

  942 ft²

Step-by-step explanation:

The diagram shows the area to be 3/4 of that of a circle of radius 20 ft. The area of a circle is given by ...

  A = πr² = π(20 ft)² = 400π ft²

Then 3/4 of that area is ...

  dog run = (3/4)(400π ft²) = 300π ft² ≈ 942.48 ft²

The area of the dog's run is about 942 ft².

3 0
3 years ago
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