Answer:
efghijklmnopqrstuvwxyz, thank me later
Answer:
Sunil = 10 and Sushil= 40
Step-by-step explanation:
Present ages-
Sushil= 4x
Sunil= x
5 years ago-
Sushil = 4x - 5
Sunil = x - 5
4x - 5 = 7(x - 5) = 4x - 5 = 7x - 35
= -5 = 3x - 35
= 30 = 3x
= 10 = x
So substitute the xs for 10-
Present Sushil= 4 x 10 = 40
Present Sunil= 10
Answer:
y = - 
x - 3
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Here m = - , thus
y = - x + c ← is the partial equation
To find c , substitute (4, - 5) into the partial equation
- 5 = - 2 + c ⇒ c = - 5 + 2 = - 3
y = - x - 3 ← equation of line
:<span> </span><span>You need to know the derivative of the sqrt function. Remember that sqrt(x) = x^(1/2), and that (d x^a)/(dx) = a x^(a-1). So (d sqrt(x))/(dx) = (d x^(1/2))/(dx) = (1/2) x^((1/2)-1) = (1/2) x^(-1/2) = 1/(2 x^(1/2)) = 1/(2 sqrt(x)).
There is a subtle shift in meaning in the use of t. If you say "after t seconds", t is a dimensionless quantity, such as 169. Also in the formula V = 4 sqrt(t) cm3, t is apparently dimensionless. But if you say "t = 169 seconds", t has dimension time, measured in the unit of seconds, and also expressing speed of change of V as (dV)/(dt) presupposes that t has dimension time. But you can't mix formulas in which t is dimensionless with formulas in which t is dimensioned.
Below I treat t as being dimensionless. So where t is supposed to stand for time I write "t seconds" instead of just "t".
Then (dV)/(d(t seconds)) = (d 4 sqrt(t))/(dt) cm3/s = 4 (d sqrt(t))/(dt) cm3/s = 4 / (2 sqrt(t)) cm3/s = 2 / (sqrt(t)) cm3/s.
Plugging in t = 169 gives 2/13 cm3/s.</span>
Answer:
b
Step-by-step explanation:
all squares have 4 sides which is a quadrilateral.
