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Sonja [21]
2 years ago
7

Which of the following purchases shows the LEAST expensive unit price?

Mathematics
1 answer:
seraphim [82]2 years ago
7 0

Step-by-step explanation:

9 apples for $4.23

Thats the answer

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81 - 35+30 (55) = 26 therefore 26cm is ur final answer
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A vendor has 12 balloons for sale: 6 are yellow, 2 are red, and 4 are green. A balloon is selected at random and sold. If the ba
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Answer is 5 over 11. I hope this may help you
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Jim Tree has $3,300 in cash and $3,300 in owners equity. The following transactions take place. You withdraw $500 for yourself,
nirvana33 [79]
3,300-500=2,800
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3 years ago
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The time intervals between successive barges passing a certain point on a busy waterway have an exponential distribution with me
lisov135 [29]

Answer:

a) <u>0.4647</u>

b) <u>24.6 secs</u>

Step-by-step explanation:

Let T be interval between two successive barges

t(t) = λe^λt where t > 0

The mean of the exponential

E(T) = 1/λ

E(T) = 8

1/λ = 8

λ = 1/8

∴ t(t) = 1/8×e^-t/8   [ t > 0]

Now the probability we need

p[T<5] = ₀∫⁵ t(t) dt

=₀∫⁵ 1/8×e^-t/8 dt

= 1/8 ₀∫⁵ e^-t/8 dt

= 1/8 [ (e^-t/8) / -1/8 ]₀⁵

= - [ e^-t/8]₀⁵

= - [ e^-5/8 - 1 ]

= 1 - e^-5/8 = <u>0.4647</u>

Therefore the probability that the time interval between two successive barges is less than 5 minutes is <u>0.4647</u>

<u></u>

b)

Now we find t such that;

p[T>t] = 0.95

so

t_∫¹⁰ t(x) dx = 0.95

t_∫¹⁰ 1/8×e^-x/8 = 0.95

1/8 t_∫¹⁰ e^-x/8 dx = 0.95

1/8 [( e^-x/8 ) / - 1/8 ]¹⁰_t  = 0.95

- [ e^-x/8]¹⁰_t = 0.96

- [ 0 - e^-t/8 ] = 0.95

e^-t/8 = 0.95

take log of both sides

log (e^-t/8) = log (0.95)

-t/8 = In(0.95)

-t/8 = -0.0513

t = 8 × 0.0513

t = 0.4104 (min)

so we convert to seconds

t = 0.4104 × 60

t = <u>24.6 secs</u>

Therefore the time interval t such that we can be 95% sure that the time interval between two successive barges will be greater than t is <u>24.6 secs</u>

6 0
2 years ago
Please do step by steps for each!
Schach [20]

Answer:

  • x² - 8x + 12
  • x³ + 2x² - 15x - 36
  • x³ -2x² - 15x

Step-by-step explanation:

#1) Find the polynomial with roots at 2 and 6

  • (x -2)(x - 6) = x² - 8x + 12

#2) Find the polynomial with a double root at -3 and another root at 4

  • (x+3)(x+3)(x-4) = (x²+6x+9)(x-4) = x³ + 2x² - 15x - 36

#3) Find the polynomial with roots 0, -3 and 5

  • (x -0)(x+3)(x-5) = x(x²-2x - 15) = x³ -2x² - 15x
3 0
3 years ago
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