<em>y</em> - 1/<em>z</em> = 1 ==> <em>y</em> = 1 + 1/<em>z</em>
<em>z</em> - 1/<em>x</em> = 1 ==> <em>z</em> = 1 + 1/<em>x</em>
==> <em>y</em> = 1 + 1/(1 + 1/<em>x</em>) = 1 + <em>x</em>/(<em>x</em> + 1) = (2<em>x</em> + 1)/(<em>x</em> + 1)
<em>x</em> - 1/<em>y</em> = <em>x</em> - (<em>x</em> + 1)/(2<em>x</em> + 1) = (2<em>x</em> ² - 1)/(2<em>x</em> + 1) = 1
==> 2<em>x</em> ² - 1 = 2<em>x</em> + 1
==> 2<em>x</em> ² - 2<em>x</em> - 2 = 0
==> <em>x</em> ² - <em>x</em> - 1 = 0
==> <em>x</em> = (1 ± √5)/2
If you start solving for <em>z</em>, then for <em>x</em>, then for <em>y</em>, you would get the same equation as above (with <em>y</em> in place of <em>x</em>), and the same thing happens if you solve for <em>x</em>, then <em>y</em>, then <em>z</em>. So it turns out that <em>x</em> = <em>y</em> = <em>z</em>.
Answer:
not factorable
Step-by-step explanation:
The easiest way to factor is to find two numbers of the "a" value (the coefficient before 
) and the factors of the c value (10) that ADD up to give you -9, in this case it would be:
1 -10 --> 1(-10) gives you -10
1 -1 --> 1(-1) gives you -1
adding these together -10 + (-1) = -11 which does not equal -9.
You could stop here and conclude that this is not factorable by inspection.
Another method: using the quadratic formula to find its roots.
Roots: 
and 
Answer:
D
Step-by-step explanation:
We know that we are adding the two expressions because the question says "sum" which means that we need to add. Let's combine like terms. We know that x + 2x = 3x and 5 + 3 = 8 so the answer is 3x + 8.
<h3>(1136+1272)-(1138+{-1250})</h3><h3>=2408-(-112)</h3><h3>=2408+112</h3><h3>=2520</h3><h3>the answer is 2520</h3><h2 /><h2 /><h2>hope it helped :-)</h2>
Answer:
(a x 4)+(a x 3)=7a
Step-by-step explanation:
(a x 4)+(a x 3)= 4a+3a
(a x 4)+(a x 3)=7a
or does your question means something else??
