A hexagon can be considered to be 6 triangles with a common vertex.
Area of 1 of the triangle = 1/2 * 2 * side length
Area of whole hexagon is 6 times this.
Answer:
D
Step-by-step explanation:
to find a term in the sequence multiply the previous term by r , then
a₄ = - 8 , so
a₅ = - 8 × 0.5 = - 4
a₆ = - 4 × 0.5 = - 2
Answer:
The graph for x-2y>=-12 needs to get y aloneso add 2y to both sides to getx >=-12 +2ythen add 12 to both sides of the in equalityx+12 >=2ynext divide each term by 2x/2 + 6 >= yy<= x/2 + 6so the graph connects (0,6) and (2,7) and shade below the solid line
Answer:
1963.2 pounds (lbs.)
Step-by-step explanation:
Things to understand before solving:
- - <u>Normal Probability Distribution</u>
- The z-score formula can be used to solve normal distribution problems. In a set with mean ц and standard deviation б, the z-score of a measure X is given by:

The Z-score reflects how far the measure deviates from the mean. After determining the Z-score, we examine the z-score table to determine the p-value associated with this z-score. This p-value represents the likelihood that the measure's value is less than X, or the percentile of X. Subtracting 1 from the p-value yields the likelihood that the measure's value is larger than X.
- - <u>Central Limit Theorem</u>
- The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean ц and standard deviation б , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean ц and standard deviation

As long as n is more than 30, the Central Limit Theorem may be applied to a skewed variable. A specific kind of steel cable has an average breaking strength of 2000 pounds, with a standard variation of 100 pounds.
This means, ц = 2000 and б = 100.
A random sample of 20 cables is chosen and tested.
This means that n = 20, 
Determine the sample mean that will exclude the top 95 percent of all size 20 samples drawn from the population.
This is the 100-95th percentile, or X when Z has a p-value of 0.05, or X when Z = -1.645. So 
- By the Central Limit Theorem


<h3>Answer:</h3>
The sample mean that will cut off the top 95% of all size 20 samples obtained from the population is 1963.2 pounds.