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mario62 [17]
3 years ago
15

What is -7+ 1/3.pos helo​

Mathematics
1 answer:
Nutka1998 [239]3 years ago
5 0

Answer:

I'm not sure exactly what you mean but, here's my answer to 7 + 1/3.

22 /3

Step-by-step explanation:

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For the following telescoping series, find a formula for the nth term of the sequence of partial sums
gtnhenbr [62]

I'm guessing the sum is supposed to be

\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}

Split the summand into partial fractions:

\dfrac1{(5k-1)(5k+4)}=\dfrac a{5k-1}+\dfrac b{5k+4}

1=a(5k+4)+b(5k-1)

If k=-\frac45, then

1=b(-4-1)\implies b=-\frac15

If k=\frac15, then

1=a(1+4)\implies a=\frac15

This means

\dfrac{10}{(5k-1)(5k+4)}=\dfrac2{5k-1}-\dfrac2{5k+4}

Consider the nth partial sum of the series:

S_n=2\left(\dfrac14-\dfrac19\right)+2\left(\dfrac19-\dfrac1{14}\right)+2\left(\dfrac1{14}-\dfrac1{19}\right)+\cdots+2\left(\dfrac1{5n-1}-\dfrac1{5n+4}\right)

The sum telescopes so that

S_n=\dfrac2{14}-\dfrac2{5n+4}

and as n\to\infty, the second term vanishes and leaves us with

\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}=\lim_{n\to\infty}S_n=\frac17

7 0
3 years ago
Which unit would you use to measure the weight of a car?<br><br> mg<br> kg<br> g<br> km
Mariulka [41]

Answer:

kg

Step-by-step explanation:

7 0
3 years ago
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Solve the system of linear equations. (enter your answers as a comma-separated list. if there is no solution, enter no solution.
Neporo4naja [7]
There is no system to solve for
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3 years ago
Josiah is buying a Christmas present for his mom. He has $24 in his saving account but needs $60 to buy the present he has in mi
olchik [2.2K]

Answer:

Step-by-step explanation:

9h + 24 = 60

6 0
2 years ago
I NEED HELP PLEASE!!!! Given a real world problem, can you find the unit rate?
Yuliya22 [10]

Here is an example:

Josh bought 7 apples for $21.

21/7 is 3, so one apple costs $3. This is the unit rate.

21/7 simplifies to 3/1, that’s another way to think about it. Simplify the fraction until the denominator is 1.

Hope this helps! Tell me if you have any questions!

3 0
3 years ago
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