From a sample with nequals=1616, the mean number of televisions per household is 22 with a standard deviation of 11 television.
using chebychev's theorem, determine at least how many of the households have between 00 and 44 televisions.
1 answer:
Chebyshev's inequality:
For a wide class of distributions, no more than
of the values can be outside of k standard deviations of the mean.
Here,
n = 16
μ = 2
σ = 1
range iin question = 0 to 4
=> k=2
meaning that at most 1/4 of the sample is outside the given range, or 3/4 of the sample= (3/4)*16 =12 is within the given range of 0 to 4 televisions.
Answer: at least 12 out of 16 households have between 0 to 4 televisions, according to the Chebyshev's inequality.
You might be interested in
Answer:
x=4
Step-by-step explanation:
4x - 3 = 2x + 5
4x - 2x = 5 + 3
2x = 8
x = 8/2
x = 4
3x+4=13
3x=13-4
3x=9
x=9/3
x=3
The number is 3 :)
Answer:
let alpha be x and beta be y
Step-by-step explanation:
x+y= -b/a
x+y=-1/6
and xy= c/a
xy= -1/3
according to question
1/x+1/y -xy =(x+y)/xy-xy
(-1/6)/(-1/3)-(-1/3)
1/2+1/3
the answer is 5/6
I’m guessing a parallelogram
1487.93 should be the correct answer I believe.