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QveST [7]
3 years ago
5

Solve a + 14 < 20. solve 6 grade math​

Mathematics
2 answers:
AnnyKZ [126]3 years ago
7 0

Answer:

a<6

Step-by-step explanation:

You need to get "A" by its self so you subtract 14 from both sides and you get the answer "A" equals less than six.

gayaneshka [121]3 years ago
7 0

Answer:

 A. can equal any number below 6

Step-by-step explanation:

There is no way to tell exactly what number a is equal to with the information given, but we do know that since  a + 14 is less than 20, a can't equal 6 or any number above it.

Hope that makes sense! :)

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the perimeter of a rectangle is 68ft the ratio of the length to the width iss 9:8 what are the dimensions of the rectangle
NikAS [45]

Answer:


Step-by-step explanation:

2 * L + 2 * W = 68  

2*L = 2* 9x = 9x + 9x  

2*W = 2*8x = 8x + 8x  

Since the perimeter is 68  

9x + 9x + 8x + 8x = 68

4 0
3 years ago
A spherical exercise ball has a maximum diameter of 30 inches when filled with air. The ball was completely empty at the start,
Alex73 [517]

Answer:

A) A(t)  =  4500*π  -  1600*t

B) A(4)  =  7730 in³

C) t  =  8,8 sec

Step-by-step explanation:

The volume of the sphere is:

d max  =  30   r max  =  15 in

V(s) =  (4/3)*π*r³      V(s)  =   (4/3)*π* (15)³

V(s) = 4500*π

A)  Amount of air needed to fill the ball A(t)

A(t)  = Total max. volume of the sphere - rate of flux of air * time

A(t)  =  4500*π  -  1600*t    in³

B) After 4 minutes

A(4)  =  4500*π  - 6400

A(4)  =  14130 - 6400

A(4)  =  7730 in³

C)  A(t)  =  4500*π  -  1600*t  

when  A(t) = 0   the ball got its maximum volume then:

4500*π -  1600*t  =  0

t  =   14130/1600

t  =  8,8 sec

8 0
3 years ago
What is the area of the figure use pi
Inessa05 [86]
Area of triangle = 1/2 (6)(5) = 15
Area of semicircle = 1/2(3.14)(3^2) = 14.13

Area of figure = 15 + 14.13 = 29.13

Answer
29.13 square units
6 0
3 years ago
Read 2 more answers
The Hudson Bay tides vary between 3 feet and 9 feet. The tide is at its lowest point when time (t) is 0 and completes a full cyc
BaLLatris [955]

Answer:

y(t)= 6-3cos(\dfrac{2\pi}{14}t )

Step-by-step explanation:

The function that could model this periodic phenomenon will be of the form

y(t) = y_0+Acos(wt)

The tide varies between 3ft and 9ft, which means its amplitude A is

A =\dfrac{(9-3)ft}{2} \\\\\boxed{A = 3ft}

and its midline y_0 is

y_o=3+3 \\\\\boxed{y_o= 6ft}.

Furthermore, since at t=0 the tide is at its lowest ( 3 feet ), we know that the trigonometric function we must use is -cos(\omega t).

The period of the full cycle is 14 hours, which means

\omega t =2\pi

\omega (t+14)= 4\pi

giving us

\boxed{\omega = \dfrac{2\pi}{14}.}

With all of the values of the variables in place, the function modeling the situation now becomes

\boxed{y(t)= 6-3cos(\dfrac{2\pi}{14}t ).}

8 0
4 years ago
How do you write (243)^ 3/5 in radical form? THEN simplified?! *PLEASE HELP
SOVA2 [1]

Answer:

27

Step-by-step explanation:

If you have an exponent that is a fraction, you need to make a radical with the index from the denominator and an exponent of the radicand from the numerator.

(243)^3/5=(\sqrt[5]{243}^3)

This would come out as \sqrt[5]{14348907^}. this further simplifies down to the final answer of 27

6 0
3 years ago
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