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AleksandrR [38]
2 years ago
15

What is the volume of a sphere with a diameter of 9.9 cm, rounded to the nearest

Mathematics
1 answer:
777dan777 [17]2 years ago
6 0

Answer:

the volume of the sphere is 507.78981 cm^3

Step-by-step explanation:

The computation of the volume of the sphere is given below:

Given that

The Diameter is 9.9 cm

So, the volume of the sphere is

= 4 ÷ 3 ×π × r^3

= 4 ÷ 3 × 3.14 × 9.9 ÷ 2^3

= 4 ÷ 3 × 3.14 × 4.95^3

= 507.78981 cm^3

Here r denotes the radius

And, the radius would be comes by dividing the diameter from 2

Hence, the volume of the sphere is 507.78981 cm^3

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The antibiotic clarithromycin is eliminated from the body according to the formula A(t) = 500e−0.1386t, where A is the amount re
PolarNik [594]

Answer:

Time(t) = 11.61 hours (Rounded to two decimal place)

Step-by-step explanation:

Given: The antibiotic  clarithromycin is eliminated from the body according to the formula:

A(t) = 500e^{-0.1386t}                 ......[1]

where;

A - Amount remaining in the body(in milligram)

t - time in hours after the drug reaches peak concentration.

Given: Amount of drug in the body is reduced to 100 milligrams.

then,

Substitute the value of A = 100 milligrams in [1] we get;

100= 500e^{-0.1386t}

Divide both sides by 500 we get;

\frac{100}{500}=\frac{ 500e^{-0.1386t}}{500}

Simplify:

\frac{1}{5} = e^{-0.1386t}

Taking logarithm both sides with base e, then we have;

\log_e (\frac{1}{5})= \log_e (e^{-0.1386t})

\log_e (\frac{1}{5})=-0.1386t         [ Using \log_e e^a =a ]

or

\log_e (0.2)=-0.1386t

-1.6094379124341 = -0.1386t

 [using value of \log_e (0.2) = -1.6094379124341 ]

then;

t = \frac{-1.6094379124341}{-0.1386}

Simplify:

t ≈11.61 hours.

Therefore, the time 11.61 hours(Rounded two decimal place) will pass before the amount of drug in the body is reduced to 100 milligrams


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Which scales are equivalent to the scale 1cm to 5km? More than one is the right answer
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Step-by-step explanation:

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Step-by-step explanation:

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