Answer:
JL = 62
Step-by-step explanation:
JL = JK + KL, substitute values
5x + 2 = 27 + 3x - 1
5x + 2 = 26 + 3x ( subtract 3x from both sides )
2x + 2 = 26 ( subtract 2 from both sides )
2x = 24 ( divide both sides by 2 )
x = 12
Thus
JL = 5x + 2 = 5(12) + 2 = 60 + 2 = 62
Answer:
see explanation
Step-by-step explanation:
To find the x- intercepts set y = 0, that is
- 2x² - 9x + 5 = 0
To factorise the quadratic consider the factors of the product of the coefficient of the x² term and the constant term that sum to give the coefficient of the x- term.
product = - 2 × 5 = - 10 and sum = - 9
The factors are - 10 and + 1
Use these factors to split the middle term
- 2x² - 10x + x + 5 = 0 ( factor the first/second and third/fourth terms )
- 2x(x + 5) + 1(x + 5) ( factor out (x + 5) )
(x + 5)(- 2x + 1) = 0
equate each factor to zero and solve for x
x + 5 = 0 ⇒ x = - 5
- 2x + 1 = 0 ⇒ x = ![\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D)
x-intercepts are x = - 5 and x = ![\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D)
The total surface area of the triangular prism that has a height of h and the side length of a is given below.
![\rm a(\dfrac{\sqrt3}{2} \ a + 3h)](https://tex.z-dn.net/?f=%5Crm%20a%28%5Cdfrac%7B%5Csqrt3%7D%7B2%7D%20%5C%20a%20%2B%203h%29)
<h3>What is a triangular prism?</h3>
A triangular prism is a closed solid that has two parallel triangular bases connected by a rectangle surface.
A box is in the shape of an equilateral triangular prism.
If the box is to be covered with paper on its lateral sides.
Let a be the side length of the equilateral triangle and h be the height of the prism.
Then the surface area of the triangular prism will be
Surface area = 2 × area of triangle + 3 × area of the rectangle
The area of the triangle will be
![\rm Area\ of\ triangle = \dfrac{\sqrt{3}a^2}{4}](https://tex.z-dn.net/?f=%5Crm%20Area%5C%20of%5C%20triangle%20%3D%20%5Cdfrac%7B%5Csqrt%7B3%7Da%5E2%7D%7B4%7D)
The area of the rectangle will be
![\rm Area \ of \ rectangle = a \ h](https://tex.z-dn.net/?f=%5Crm%20Area%20%5C%20of%20%5C%20rectangle%20%3D%20a%20%5C%20h)
Then the total surface area will be
![\rm Surface\ area = 2 \times \dfrac{\sqrt3 a^2 }{4} + 3 ah\\\\\\Surface\ area = a(\dfrac{\sqrt3}{2} \ a + 3h)](https://tex.z-dn.net/?f=%5Crm%20Surface%5C%20area%20%3D%20%202%20%5Ctimes%20%5Cdfrac%7B%5Csqrt3%20a%5E2%20%7D%7B4%7D%20%2B%203%20ah%5C%5C%5C%5C%5C%5CSurface%5C%20area%20%3D%20%20a%28%5Cdfrac%7B%5Csqrt3%7D%7B2%7D%20%5C%20a%20%2B%203h%29)
More about the triangular prism link is given below.
brainly.com/question/21308574
Answer:
B. (1, 2)
D. (-10, 1)
Step-by-step explanation:
Both points land in the highlighted area.
Hope this helps! :)
Answer:
YOUR ANSWER IS 35 HOPE THIS HELPS
Step-by-step explanation: